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anonymous
 one year ago
Could someone explain how to do these problems?
Find the first six terms of the sequence.
a1 = 3, an = 2 ● an1
anonymous
 one year ago
Could someone explain how to do these problems? Find the first six terms of the sequence. a1 = 3, an = 2 ● an1

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2n = term that you have to find so to find 2nd term replace n by 2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm, a_1=3\] \[\huge\rm a_n=2 \times a_{n1}\] substitute n for 2 \[\huge\rm a_n=2 \times a_{21}\] 21 = 1 then substitute a_1 for 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so...would it be: 3, 6, 12, 24, 48, 96 @Nnesha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[a_{1}=3\]\[a_{n}=2 \times a_{n1}\] That is to say each term is equal to twice the previous term, if you are given the first term as 3 u can calculate upto as many terms as u like, each successive term is twice the last term second term will be 2 times the first time, 3rd term will be 2 times 2nd term and so on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could you help me with another one? @Nishant_Garg

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the standard form of the equation of the parabola with a focus at (0, 6) and a directrix at y = 6. @Nishant_Garg I never know quite where to start.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hm I think the equation will be \[x^2=4ay\] Becuase the focus lies on the y axis, the equation must be either the form of \[x^2=4ay\] Or \[x^2=4ay\] But since the equation of directrix has a minus sign, it implies the the equation should be the first one dw:1439736294431:dw The first figure makes sense because the directrix is suppose to be like in front the parabola Also you are given \[a=6\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so just plug that a into the equation
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