Could someone explain how to do these problems?
Find the first six terms of the sequence.
a1 = -3, an = 2 ● an-1

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- anonymous

- schrodinger

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- Nnesha

n = term that you have to find
so to find 2nd term replace n by 2

- sohailiftikhar

a1=-3

- Nnesha

\[\huge\rm, a_1=3\]
\[\huge\rm a_n=2 \times a_{n-1}\]
substitute n for 2
\[\huge\rm a_n=2 \times a_{2-1}\]
2-1 = 1
then substitute a_1 for -3

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## More answers

- anonymous

Ok so...would it be:
-3, -6, -12, -24, -48, -96
@Nnesha

- Nnesha

:)

- anonymous

\[a_{1}=-3\]\[a_{n}=2 \times a_{n-1}\]
That is to say each term is equal to twice the previous term, if you are given the first term as -3 u can calculate upto as many terms as u like, each successive term is twice the last term
second term will be 2 times the first time, 3rd term will be 2 times 2nd term and so on

- anonymous

looks good!

- anonymous

Could you help me with another one? @Nishant_Garg

- anonymous

Find the standard form of the equation of the parabola with a focus at (0, 6) and a directrix at y = -6.
@Nishant_Garg I never know quite where to start.

- anonymous

hm I think the equation will be
\[x^2=4ay\]
Becuase the focus lies on the y axis, the equation must be either the form of
\[x^2=4ay\]
Or \[x^2=-4ay\]
But since the equation of directrix has a minus sign, it implies the the equation should be
the first one
|dw:1439736294431:dw|
The first figure makes sense because the directrix is suppose to be like in front the parabola
Also you are given
\[a=6\]

- anonymous

so just plug that a into the equation

- anonymous

Thank you!

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