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anonymous

  • one year ago

Could someone explain how to do these problems? Find the first six terms of the sequence. a1 = -3, an = 2 ● an-1

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  1. Nnesha
    • one year ago
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    n = term that you have to find so to find 2nd term replace n by 2

  2. sohailiftikhar
    • one year ago
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    a1=-3

  3. Nnesha
    • one year ago
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    \[\huge\rm, a_1=3\] \[\huge\rm a_n=2 \times a_{n-1}\] substitute n for 2 \[\huge\rm a_n=2 \times a_{2-1}\] 2-1 = 1 then substitute a_1 for -3

  4. anonymous
    • one year ago
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    Ok so...would it be: -3, -6, -12, -24, -48, -96 @Nnesha

  5. Nnesha
    • one year ago
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    :)

  6. anonymous
    • one year ago
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    \[a_{1}=-3\]\[a_{n}=2 \times a_{n-1}\] That is to say each term is equal to twice the previous term, if you are given the first term as -3 u can calculate upto as many terms as u like, each successive term is twice the last term second term will be 2 times the first time, 3rd term will be 2 times 2nd term and so on

  7. anonymous
    • one year ago
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    looks good!

  8. anonymous
    • one year ago
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    Could you help me with another one? @Nishant_Garg

  9. anonymous
    • one year ago
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    Find the standard form of the equation of the parabola with a focus at (0, 6) and a directrix at y = -6. @Nishant_Garg I never know quite where to start.

  10. anonymous
    • one year ago
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    hm I think the equation will be \[x^2=4ay\] Becuase the focus lies on the y axis, the equation must be either the form of \[x^2=4ay\] Or \[x^2=-4ay\] But since the equation of directrix has a minus sign, it implies the the equation should be the first one |dw:1439736294431:dw| The first figure makes sense because the directrix is suppose to be like in front the parabola Also you are given \[a=6\]

  11. anonymous
    • one year ago
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    so just plug that a into the equation

  12. anonymous
    • one year ago
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    Thank you!

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