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im not asking for the answer, i just wanted to know how to do it . i think i know but im not sure
@Vocaloid Should I try?
go for it, you don't need my permission
lmao, do i have to just substitute each point and whichever one gives the right answer is the correct one ?
that's one way to do it, but... there might be an easier way since it gives you two inequalities and a graph, try graphing 2x + y ≤ 10 2x - 4y < 8 and take all the points that fall within the solution set
first of all you have to put random points and see what the line is (graph) 2x+y=10 (let) see, 5,0 and 0,10 satisfies
now draw a line between these two points
now when it is <=10 that means it is the shaded portion towards the origin from the line
@Vocaloid could you verify me for the first question?
do the second in a similar way.....@bullkidd Are you getting it?
yeeeeeeeeeeep thank youuu
and who should i give a medal to , lol
Its your wish..... @bullkidd
first draw the line ax+by=c by finding any two points on the line if \[c \neq 0\] then put x=0,y=0 in the given equation to see if the origin lies in the region if the equality is true ,origin lies in the region if false origin does not lie in the region. if c=0, then put x=1 or any other integer and y=0 and repeat the same.