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anonymous
 one year ago
help, medal and fan
The following is the graph of f(x) = 3(x  3)2 + 1.
anonymous
 one year ago
help, medal and fan The following is the graph of f(x) = 3(x  3)2 + 1.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do i solve the problem?

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2All you have to do is find out if it's true or false

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There are a couple different ways you could approach this. The equation is already provided, you just need to know if it's the correct equation for the graph. You could pick points on the graph and plug them into the equation to see if they fit, or just think back to the vertex form equation...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know, but how do i know? like should i solve the problem for x to see if its right? online schooling gets confusing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0woo, getting more confussed, to many people replying, my computer being slow to catch up lol

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2no it's true plug in (3,1) \(f(x) = 3(x  3)^2 + 1\\1=3(33)^2+1\\33=0\\0^2=0\\3*0=0\\1=1\) another point (2,4) \(4= 3(2  3)2 + 1\\4=3*1^2+1\\1^2=1\\3*1=3\\3+1=4\\4=4\)

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2@sohailiftikhar is wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i see what you mean @Mehek14 .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Penguin7 , I agree with @Mehek14 !

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2how am I wrong when the solutions are correct?

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2if you want more proof, why don't you graph it using desmos?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0desmos confuses me..just saying lol

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2because that is one of the points in the parabola

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2so it has to be a solution in the equation if the equation is true

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2the output of x=1 is not shown in the graph that @Penguin7 attached

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Using the vertex form equation, h is how far the graph moves to the right and +k is how far up it moves. Your graph moved 3 to the right and 1 up so that gets you to y=a(x3)^2+1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0to find a, you can plug in values...(2,4) and (4,4) are clearly visible on the graph.

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2this matches the graph that was attached

Mehek14
 one year ago
Best ResponseYou've already chosen the best response.2you have (3,1), (2,4), and (4,4) in both graphs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, can we all agree that @Mehek14 is right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Penguin7 , yes!!! @Mehek14 is correct. If it helps you decide at all, I am a math teacher. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay. well, i hope both you and @Mehek14 are okay will me taging u both..bc i know ill need help.
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