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mathmath333

  • one year ago

Probablity Question

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  1. mathmath333
    • one year ago
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    A die is thrown three times. Events A and B are defined as below: A : 4 on the third throw B : 6 on the first and 5 on the second throw Find the probability of A given that B has already occurred

  2. ParthKohli
    • one year ago
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    Don't you think that the first, second, and the third throws are independent of each other?

  3. ParthKohli
    • one year ago
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    If we got six on the first throw, and five on the second, how does that affect the probability of four occurring on the third throw?

  4. mathmath333
    • one year ago
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    1,2, and 3 are different

  5. mathmath333
    • one year ago
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    need to use conditional probablity , i dont know how they affect

  6. ParthKohli
    • one year ago
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    They don't. The probability is 1/6.

  7. mathmath333
    • one year ago
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    1/6 for which ?

  8. ParthKohli
    • one year ago
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    We're given that B has already occurred. But who cares about what has occurred? We just want to see what the probability of getting a 4 is on the third throw. That is 1/6.

  9. mathmath333
    • one year ago
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    but i need to solve this by conditional probablity

  10. mathmath333
    • one year ago
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    if 4 had occured in 1st or 2nd place then

  11. mathmath333
    • one year ago
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    will it would have been 1/4 as usual

  12. ParthKohli
    • one year ago
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    OK, the probability is either 1/6 * 1/6 * 1/6 or just 1/6 depending on the use of "given that B has already occurred".

  13. mathmath333
    • one year ago
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    lol m getting confused

  14. anonymous
    • one year ago
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    what PK said is correct but if you want to do it conditional probability then here it is P(A/B) = P(A (intersection) B ) / P(B) P(A (intersection) B ) is the event where all the 3 throws have some specified values P(B) is the event where only 2 are specified I hope you can calculate both values

  15. thomas5267
    • one year ago
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    It is 1/6 as A and B are independent. No matter B happened or not, the probability of A happening is the same. Past results of die throws does not affect the future results of die throws. Basically it is what ParthKohli is saying.

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