yeval76
  • yeval76
Cylinder A has a radius of 12 inches and a height of 6 inches. Cylinder B has a volume of 648π. What is the percent change in volume between cylinders A and B? Cylinder B is 50% smaller than cylinder A. Cylinder B is 25% smaller than cylinder A. Cylinder B is 150% bigger than cylinder A. Cylinder B is 200% bigger than cylinder A.
Mathematics
jamiebookeater
  • jamiebookeater
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yeval76
  • yeval76
yeval76
  • yeval76
mathstudent55
  • mathstudent55
First, find the volume of cylinder A.

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mathstudent55
  • mathstudent55
Do you know how to find the volume of a cylinder?
yeval76
  • yeval76
The volume of cylinder A is 2,712.96
mathstudent55
  • mathstudent55
\(\Large V_{cylinder} = \pi r^2 h\) where r = radius of the base, and h = height of the cuylinder
yeval76
  • yeval76
Yea so the volume of cylinder A is 2,712.96
yeval76
  • yeval76
So what do I do now?
mathstudent55
  • mathstudent55
Correct. Since the volume of cylinder B is written in terms of pi, you can also write the volume of cylinder A in terms of pi. (In other words, don't multiply pi in the formula.) \(\Large V_{A} = 864 \pi\) \(\Large V_B = 648 \pi\) Ok so far?
yeval76
  • yeval76
Yes mam or sir
yeval76
  • yeval76
Would you divide Va by Vb and then multiply it by 100...
mathstudent55
  • mathstudent55
Now we need the second step of the problem. We need to find the percent change. Look in all choices. Every choice states "Cylinder B is ... than cylinder A." This means we are comparing cylinder B to A.
mathstudent55
  • mathstudent55
Here is the formula to calculate percent change: \(percent~change = \dfrac{new~amount - old~amount}{old~amount} \times 100\) If the percent change is positive, it is an increase. If the percent change is negative, it is a decrease. In this case, since we are comparing cylinder B to cylinder A, then old amount = 864 pi new amount = 648 pi (pi will cancel out in the calculation.)
yeval76
  • yeval76
So will it be 25% smaller then cylinder A right?
mathstudent55
  • mathstudent55
Correct.
yeval76
  • yeval76
Yayyyy Thank You!!! @mathstudent55
mathstudent55
  • mathstudent55
You're welcome.

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