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anonymous

  • one year ago

am i correct

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  1. anonymous
    • one year ago
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  2. mathstudent55
    • one year ago
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    Notice that each choice has the % sign in it. 6% in 1 year (12 months) is what percent in 1 month?

  3. anonymous
    • one year ago
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    okay but can you say if im correct or not please

  4. mathstudent55
    • one year ago
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    You are not correct.

  5. mathstudent55
    • one year ago
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    6% in 12 months is ? in 1 month?

  6. anonymous
    • one year ago
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    ok so my second option was d so is d correct ? iwill fan and medal you

  7. mathstudent55
    • one year ago
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    Correct. 6%/12 months = 0.5%/1 month

  8. anonymous
    • one year ago
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    thanks bro!

  9. anonymous
    • one year ago
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    @mathstudent55

  10. mathstudent55
    • one year ago
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    yw

  11. anonymous
    • one year ago
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  12. anonymous
    • one year ago
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    @mathstudent55 am icorrect here too

  13. anonymous
    • one year ago
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    @mathstudent55

  14. mathstudent55
    • one year ago
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    You are correct.

  15. mathstudent55
    • one year ago
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    This question is a bit strange. Up to step 3, the problem is 100% correct. In step 4, decimals were written for the logs. Step 4 may or may not be a mistake depending on whether an exact answer or an approximation is asked for. Step 5 is definitely incorrect because the division of the decimals on the right side is incorrect. If there is no choice of Step 5, then step 4 has to be the error, but I don't agree with the question.

  16. mathmate
    • one year ago
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    @jammy987 On the first question, the question asks the rate of "decay"each month, which is a hint that the decay is cumulative, which accumulates over a year to give a depreciation of 6%, or 0.94 of the previous year. Therefore we need to solve for k in (1-k)^12=(1-0.06) take the twelfth root on both sides, (1-k)=(0.94)^(1/12)=0.994857 k=1-0.994857=0.005143. Check: (1-0.005143)^12=0.940000=depreciation of 6%

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spraguer (Moderator)
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