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anonymous
 one year ago
I'm having trouble with some partial fraction decomposition problems. I have to write out the form of the partial fraction of the function Q = limit(1 to 10) 1x/(x^2+6x+9) dx. Determine the numerival values of the coefficients, A and B A/denominator + B/denominator
anonymous
 one year ago
I'm having trouble with some partial fraction decomposition problems. I have to write out the form of the partial fraction of the function Q = limit(1 to 10) 1x/(x^2+6x+9) dx. Determine the numerival values of the coefficients, A and B A/denominator + B/denominator

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triciaal
 one year ago
Best ResponseYou've already chosen the best response.0start by finding the factors of the denominator

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439752537963:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I did that and got (x+3)^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is it really?? I thought I had to reduce after that point

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And what about the limit? The homework program I'm using says that's wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well it is wrong stop looking for handouts duhhh

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0do you need to integrate the function and find value of 10 minus value of 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not, I just need help getting to the next point. I had factored it, then put it in the form \[\frac{ 1x }{ (x+3)(x+3) } = \frac{ A }{ (x+3) } + \frac{ B }{ (x+3) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then I guess I'm supposed to find where x = 0 and solve for A then insert to find B, but I'm having a tough time just isolating just one, normally the factors wouldn't be the same thing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've just been struggling on this problem for a while now

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0how do you know the denominator for A or B is not (x +3)^2

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439753193971:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439753340124:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wow drawing is hard on this

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2you need to square the second one, try this \[\frac{ 1x }{ (x+3)(x+3) } = \frac{ A }{ (x+3) } + \frac{ B }{ (x+3)^{\color{red}{2}} }\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2then \[A(x+3)^2+B(x+3)=x\] is the next step you need the square when you have repeated factors in the denominator

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2oh wait i think i made a mistake there

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2when you add you should get \[A(x+3)+B\] as your numerator, so \[A(x+3)+B=x\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2multiply out, get \[Ax+3A+B=x\]telling you \(A=1\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2and you can get the value of \(B\) easily, simply plugin \(x=3\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2and \[3A+B=0\]so \[3+B=0\\ B=3\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2or @ganeshie8 way works too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh my goodness thank you guys so much!

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2\[\color\magenta\heartsuit\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do I close this problem? First question I've asked on here...

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2you should see an option in the bottom for "close question"
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