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anonymous
 one year ago
The following is the graph of
anonymous
 one year ago
The following is the graph of

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im over thinking it? or wow its hard..

BioHazard9064
 one year ago
Best ResponseYou've already chosen the best response.0I would say false

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0actually it is true it looks just like the graph of \(y=\sqrt[3]{x}\) only shifted to the right three units, which is what happens when you do \[y=\sqrt[3]{x3}\]

BioHazard9064
 one year ago
Best ResponseYou've already chosen the best response.0i graphed it but I could be wrong

BioHazard9064
 one year ago
Best ResponseYou've already chosen the best response.0oh i over looked the first 3 xD

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0you are supposed to know two things hers a) what \(y=\sqrt[3]{x}\) looks like and b) what happens when you replace \(x\) by \(x3\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The domain should be x >= 3 since rooting negatives results in imaginary numbers, so I think the graph should have started at x=3 if the graph was true

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would say yes. because everything before x=3 should not be graphed
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