## anonymous one year ago The following is the graph of

1. anonymous

look at graph

2. anonymous

@BioHazard9064

3. BioHazard9064

wow

4. anonymous

im over thinking it? or wow its hard..

5. BioHazard9064

I would say false

6. anonymous

why?

7. misty1212

actually it is true it looks just like the graph of $$y=\sqrt[3]{x}$$ only shifted to the right three units, which is what happens when you do $y=\sqrt[3]{x-3}$

8. BioHazard9064

i graphed it but I could be wrong

9. BioHazard9064

oh i over looked the first 3 xD

10. misty1212

you are supposed to know two things hers a) what $$y=\sqrt[3]{x}$$ looks like and b) what happens when you replace $$x$$ by $$x-3$$

11. anonymous

so it true?

12. anonymous

The domain should be x >= 3 since rooting negatives results in imaginary numbers, so I think the graph should have started at x=3 if the graph was true

13. anonymous

so false?

14. anonymous

I would say yes. because everything before x=3 should not be graphed