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anonymous

  • one year ago

The following is the graph of

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  1. anonymous
    • one year ago
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    look at graph

  2. anonymous
    • one year ago
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    @BioHazard9064

  3. BioHazard9064
    • one year ago
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    wow

  4. anonymous
    • one year ago
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    im over thinking it? or wow its hard..

  5. BioHazard9064
    • one year ago
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    I would say false

  6. anonymous
    • one year ago
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    why?

  7. misty1212
    • one year ago
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    actually it is true it looks just like the graph of \(y=\sqrt[3]{x}\) only shifted to the right three units, which is what happens when you do \[y=\sqrt[3]{x-3}\]

  8. BioHazard9064
    • one year ago
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    i graphed it but I could be wrong

  9. BioHazard9064
    • one year ago
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    oh i over looked the first 3 xD

  10. misty1212
    • one year ago
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    you are supposed to know two things hers a) what \(y=\sqrt[3]{x}\) looks like and b) what happens when you replace \(x\) by \(x-3\)

  11. anonymous
    • one year ago
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    so it true?

  12. anonymous
    • one year ago
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    The domain should be x >= 3 since rooting negatives results in imaginary numbers, so I think the graph should have started at x=3 if the graph was true

  13. anonymous
    • one year ago
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    so false?

  14. anonymous
    • one year ago
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    I would say yes. because everything before x=3 should not be graphed

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spraguer (Moderator)
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