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#taramgrant0543664 help please
I'm sorry I can't see part of the reaction it's up a little high and too much too the right, I'm on my iPad so it likes to be difficult I see CuO+H2-->Cu + That's all that I see I'm assuming if I have the reactants right it should be CuO+H2 --> Cu+ H2O
So when dealing with redox reactions most people have a saying that helps them remember mine is LEO the lion says GER LEO meanings lose electrons oxidized GER meaning gain electrons reduced For this question we need to determine which one loses electrons to become oxidized
CuO + H2 --> Cu + H20 We need to figure out the charges on each of the elements (+2)(-2)..(0) -->(0)..(+1)(-2)
As you can see oxygens charge remains at -2 so oxygen is neither oxidized or reduced
Cu goes from a charge of +2 to 0 H goes from a charge of 0 to +1 Which one is losing electrons?
The element that is oxidized is the one that loses electrons so it becomes more positive
Cu goes from a charge of +2 to 0 H goes from a charge of 0 to +1 One is gaining electrons and therefore reduced One is losing electrons therefore oxidized