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anonymous
 one year ago
help, 57 and 58. medal and fan
anonymous
 one year ago
help, 57 and 58. medal and fan

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, starting with 57, they give you an equation and they want to know if r=9 is a solution. All you have to do is plug in 9 for r on both sides of the equation and solve. If both sides balance out then it's a solution, if they don't it's not a solution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 2r }{ 5 }+\frac{ 3r }{ 5 }=\frac{ r+2 }{ 3 }\] \[\frac{ 29 }{ 5 }+\frac{ 3\times9 }{ 5 }=\frac{ 9+2 }{ 3 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's not what I got...work on the numerators first...29=? and 3x9=?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0perfect, so you have 7/5+27/5...what do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0common denominators means you can add the numerators...denominator stays the same.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0good, now what about the right side of the equation...(r+2)/3?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0exactly, so now you just need to ask yourself if 4=11/3. Then you'll have your answer!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it's been awhile since I've done a problem like that. I'm solving it now so I can hopefully help you :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, so in theory I have an answer. I'm just going to check quick to be sure!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my original work gave me an answer of 4/3, but when I plug it in it doesn't work out right.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry, it's just been too long...I can't remember how to do it correctly. :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats okay. its jst one question! ill jst make a educational guess
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