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anonymous

  • one year ago

help, 57 and 58. medal and fan

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    Ok, starting with 57, they give you an equation and they want to know if r=9 is a solution. All you have to do is plug in 9 for r on both sides of the equation and solve. If both sides balance out then it's a solution, if they don't it's not a solution.

  3. anonymous
    • one year ago
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    so 2-9/5?

  4. anonymous
    • one year ago
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    \[\frac{ 2-r }{ 5 }+\frac{ 3r }{ 5 }=\frac{ r+2 }{ 3 }\] \[\frac{ 2-9 }{ 5 }+\frac{ 3\times9 }{ 5 }=\frac{ 9+2 }{ 3 }\]

  5. anonymous
    • one year ago
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    i got 5.6=9.66

  6. anonymous
    • one year ago
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    that's not what I got...work on the numerators first...2-9=? and 3x9=?

  7. anonymous
    • one year ago
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    -7 and 27

  8. anonymous
    • one year ago
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    perfect, so you have -7/5+27/5...what do you get?

  9. anonymous
    • one year ago
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    common denominators means you can add the numerators...denominator stays the same.

  10. anonymous
    • one year ago
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    20/5=4

  11. anonymous
    • one year ago
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    good, now what about the right side of the equation...(r+2)/3?

  12. anonymous
    • one year ago
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    11/3

  13. anonymous
    • one year ago
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    exactly, so now you just need to ask yourself if 4=11/3. Then you'll have your answer!

  14. anonymous
    • one year ago
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    thank you

  15. anonymous
    • one year ago
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    what about 58?

  16. anonymous
    • one year ago
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    it's been awhile since I've done a problem like that. I'm solving it now so I can hopefully help you :)

  17. anonymous
    • one year ago
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    thank you !!!!!

  18. anonymous
    • one year ago
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    ok, so in theory I have an answer. I'm just going to check quick to be sure!

  19. anonymous
    • one year ago
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    okay

  20. anonymous
    • one year ago
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    my original work gave me an answer of 4/3, but when I plug it in it doesn't work out right.

  21. anonymous
    • one year ago
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    I'm sorry, it's just been too long...I can't remember how to do it correctly. :(

  22. anonymous
    • one year ago
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    thats okay. its jst one question! ill jst make a educational guess

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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