anonymous
  • anonymous
Evaluate S5 for 600 + 300 + 150 + … and select the correct answer below.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1,162.5 581.25 37.5<--my answer 18,600
anonymous
  • anonymous
@surjithayer
anonymous
  • anonymous
it should be greater than 1050 600+300+150+75+37.5=?

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More answers

anonymous
  • anonymous
I suppose so? Isn't it a geometric series?
anonymous
  • anonymous
correct.
anonymous
  • anonymous
So, would I be correct?
anonymous
  • anonymous
hold on.
anonymous
  • anonymous
600{(1/2)^5-1}/(1/2-1)
anonymous
  • anonymous
@phi
anonymous
  • anonymous
116.5 Am I right?
zepdrix
  • zepdrix
You're adding up 5 numbers. The first of which is 600. How did they then add up to 116.5? :o That's even smaller than the first number that you're adding... You silly billy -_-
anonymous
  • anonymous
:D! Hahaha whoops! So what should I do?
zepdrix
  • zepdrix
\[\large\rm S_n=a_1\frac{1-r^n}{1-r}\]So you determined that your common ratio, \(\large\rm r\), is 1/2 since you're dividing by 2 each time. So we'll plug in all of the information, \[\large\rm S_5=600\cdot \frac{1-\left(\frac{1}{2}\right)^5}{1-\frac{1}{2}}\]
zepdrix
  • zepdrix
And then let mr calculator do the rest :O understand how to punch it all in?
anonymous
  • anonymous
Not really, but I'll try :)
anonymous
  • anonymous
So, for the fraction part I got 1.9375.
zepdrix
  • zepdrix
If you want to punch it all in at once, I would try something like this,\[\large\rm 600*((1-.5\wedge5)\div(1-.5))\]Otherwise, if you like to do it piece by piece, that's fine also :)
zepdrix
  • zepdrix
(I replaced 1/2 with .5 in my calculator so it's easier to deal with).
anonymous
  • anonymous
Ok:) Then, i got 1162.5 as an answer :)
zepdrix
  • zepdrix
1.9375? That sounds correct for your fractional part. Then finally 1162.5? Yayyy good job!
anonymous
  • anonymous
Yippee!!! If, I post another one will you answer it? And thanks so much btw!!!
zepdrix
  • zepdrix
I'm hungrehhh, I need to make some foods :P but ya I'll try to come look if I get a chance. You can use the @zepdrix and it'll get my attention better than the message box.
anonymous
  • anonymous
Ok, thanks so much:)

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