linear equation 5a+11=a-13

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linear equation 5a+11=a-13

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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So are we solving for a then?
yes why do people keep saying that??

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Other answers:

Well it's always good to confirm what the OP is asking for. There are a lot of people on this site who ask their questions in a confusing way so I've just come to confirm at the start rather than later on lol
kk
Anyways, the way to go about solving this one would be to get all of the a values on one side and all of the number values on the other side.
5a+a first right
Well a is already positive on the right side, so to bring it over we would subtract it.
In other words 5a-a
  • phi
you might think like this: how do I *get rid of a on the right side* ? answer: add -a but to keep things equal, you also add -a to the left side.
  • phi
ok but not just 4. it is 5 a's take away 1 a.
open study whenever i get on its always acting wierd
6a
  • phi
start over, and to it carefully 5a+11=a-13 add -a to both sides. what do you get? (and write out the whole equation)
hold on one sec i need to draw it and it wont let me i'm going to refresh the page.
|dw:1439758244788:dw|
  • phi
ok, except a+a is not 0 (it is 2a) try adding -a to both sides
7a then.
  • phi
start over, 5a+11=a-13 add -a to both sides. Just write -a on both sides. can you do that ?
can you show me the steps to the answer i already know the answer its -6
of how you would you do it
  • phi
yes, we will get the answer. I would add -a to both sides. that means write -a on both sides can you try to do that ?
can you show me in drawing of how the step would be?
  • phi
you write -a on both sides , like this 5a+11 -a =a-13 - a
  • phi
if we look just at the "a" part , on the right side you have 1a take away 1 a on the left side you have 5 a's take away 1 a
so its 4a?
  • phi
can you write out the whole equation? start with 5a+11 -a =a-13 - a and simplify both sides. can you do that ?
yea sure one sec.
5a+-a=a-13a ? is that what i would do on the right side
  • phi
you start with 5a+11 -a =a+ -13 + -a you can switch the order of the right side (if you want) to 5a+11 -a =a+ -a + -13 what is a+ -a ?
2a?
  • phi
what is 1+ -1 ?
0
  • phi
and 2+ -2 or 3+ -3 or a+ -a always adds up to 0
kk
  • phi
5a+11 -a =a+ -a + -13 the right side, a+ -a is 0 so you get 5a + 11 -a = 0 + -13 0 + -13 is -13 , right?
yes
  • phi
so far we figured out 5a + 11 -a = -13 now look at the left side. it says 5 a's and 11 and take away 1 a we can simplify 5 a's take away 1 a.
4a
no sorry 6a
  • phi
ok, but try to get in the habit of writing the whole equation 5 a's take away 1 a is 4 a"s (we write it 4a) what is the whole equation?
so it is 4a?
  • phi
yes. if you had 5 cows and took away 1 cow, how many cows would you have? it works the same for a's
4a+11=-13
  • phi
notice if you could make the 11 "go away" you would have 4a by itself luckily we can make 11 go away. we add -11 and we have to add -11 to the other side to keep things equal write -11 on both sides.
then subtract 11to both sides 24 so then it would be 4a=-24
  • phi
yes. if we do it this way: 4a+11+-11=-13+-11 then on the left we have 11+-11 which is 0 (just like a+-a is zero) and on the right side -13 + -11 is -24 so you have 4a = -24 the last step is to divide both sides by 4 \[ \frac{4a}{4} = \frac{-24}{4} \]
  • phi
it might not be obvious , by 4a/4 is just a
-6 thanks
a=-6
  • phi
yes. good job. if you do a bunch of these problems, it will start to make sense.
thanks again. :)

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