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anonymous

  • one year ago

Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below.

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  1. anonymous
    • one year ago
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    Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below. 177,147 88,572<---my answer 88,575 177,144

  2. welshfella
    • one year ago
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    first term = a = 3 10th term = ar^9 = 59,049 ar^9 / a = r^9 r^9 = 59049 / 3= 19683 r = ninth root of 19683 use ur calc to find this

  3. anonymous
    • one year ago
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    88,575 is what I got :) Am I right?

  4. anonymous
    • one year ago
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    @Mehek14

  5. welshfella
    • one year ago
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    S10 = 3 * 3^10 - 1 ------- 3 - 1

  6. anonymous
    • one year ago
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    88573

  7. welshfella
    • one year ago
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    i make it 88572

  8. anonymous
    • one year ago
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    177146/2=88572 :) Thanks so much!

  9. welshfella
    • one year ago
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    yw

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