i need help on a math problem

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i need help on a math problem

Mathematics
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heres what is looks like
|dw:1439762357724:dw|
solve for x

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Other answers:

does that say square root of x +4-3=1
thats a minus not a division my bad really bad at drawing
I'm sorry, I'm still not following. Can you type the problem out please.
\[\sqrt{4}-3=1\]
sorry typed wrong\[\sqrt{X+4}-3=1\]
ok! got it...to solve for x, you have to get x by itself.
start by moving what's outside of the radical to the other side..
i need to know how like the steps please
\[\sqrt{x+4}-3=1\] get rid of the 3 on the left side of the equation, by adding 3 to both sides. so..\[\sqrt{x+4}-3+3=1+3\]
now you have\[\sqrt{x+4}=4\]
what next please
next deal with the square root...how do you think you "undo" a square root?
subtract another square root idk
ok, try this...what's \[\sqrt{25}\]
5
oh so do you just simplify it
ok, so square root of 25 is 5...how do you get it back to 25?
5*5
times
perfect! you squared it! so to undo a square root you square it!
5 times 5
\[\sqrt{x+4}^{2}=4^{2}\]
16
by raising the square root to a power of 2, you pretty much undo it all so you're left with x+4=16
solve for x
12
@nigel305 , what do you think?
thanks lol
simplier
I need a medal since i help
sorry cant she was first

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