## anonymous one year ago i need help on a math problem

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1. anonymous

heres what is looks like

2. anonymous

|dw:1439762357724:dw|

3. anonymous

solve for x

4. anonymous

does that say square root of x +4-3=1

5. anonymous

thats a minus not a division my bad really bad at drawing

6. anonymous

I'm sorry, I'm still not following. Can you type the problem out please.

7. anonymous

$\sqrt{4}-3=1$

8. anonymous

sorry typed wrong$\sqrt{X+4}-3=1$

9. anonymous

ok! got it...to solve for x, you have to get x by itself.

10. anonymous

start by moving what's outside of the radical to the other side..

11. anonymous

i need to know how like the steps please

12. anonymous

$\sqrt{x+4}-3=1$ get rid of the 3 on the left side of the equation, by adding 3 to both sides. so..$\sqrt{x+4}-3+3=1+3$

13. anonymous

now you have$\sqrt{x+4}=4$

14. anonymous

15. anonymous

next deal with the square root...how do you think you "undo" a square root?

16. anonymous

subtract another square root idk

17. anonymous

ok, try this...what's $\sqrt{25}$

18. anonymous

5

19. anonymous

oh so do you just simplify it

20. anonymous

ok, so square root of 25 is 5...how do you get it back to 25?

21. anonymous

5*5

22. anonymous

times

23. anonymous

perfect! you squared it! so to undo a square root you square it!

24. anonymous

5 times 5

25. anonymous

$\sqrt{x+4}^{2}=4^{2}$

26. anonymous

16

27. anonymous

by raising the square root to a power of 2, you pretty much undo it all so you're left with x+4=16

28. anonymous

solve for x

29. anonymous

12

30. anonymous

@nigel305 , what do you think?

31. anonymous

thanks lol

32. anonymous

simplier

33. anonymous

I need a medal since i help

34. anonymous

sorry cant she was first