anonymous
  • anonymous
i need help on a math problem
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
heres what is looks like
anonymous
  • anonymous
|dw:1439762357724:dw|
anonymous
  • anonymous
solve for x

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More answers

anonymous
  • anonymous
does that say square root of x +4-3=1
anonymous
  • anonymous
thats a minus not a division my bad really bad at drawing
anonymous
  • anonymous
I'm sorry, I'm still not following. Can you type the problem out please.
anonymous
  • anonymous
\[\sqrt{4}-3=1\]
anonymous
  • anonymous
sorry typed wrong\[\sqrt{X+4}-3=1\]
anonymous
  • anonymous
ok! got it...to solve for x, you have to get x by itself.
anonymous
  • anonymous
start by moving what's outside of the radical to the other side..
anonymous
  • anonymous
i need to know how like the steps please
anonymous
  • anonymous
\[\sqrt{x+4}-3=1\] get rid of the 3 on the left side of the equation, by adding 3 to both sides. so..\[\sqrt{x+4}-3+3=1+3\]
anonymous
  • anonymous
now you have\[\sqrt{x+4}=4\]
anonymous
  • anonymous
what next please
anonymous
  • anonymous
next deal with the square root...how do you think you "undo" a square root?
anonymous
  • anonymous
subtract another square root idk
anonymous
  • anonymous
ok, try this...what's \[\sqrt{25}\]
anonymous
  • anonymous
5
anonymous
  • anonymous
oh so do you just simplify it
anonymous
  • anonymous
ok, so square root of 25 is 5...how do you get it back to 25?
anonymous
  • anonymous
5*5
anonymous
  • anonymous
times
anonymous
  • anonymous
perfect! you squared it! so to undo a square root you square it!
anonymous
  • anonymous
5 times 5
anonymous
  • anonymous
\[\sqrt{x+4}^{2}=4^{2}\]
anonymous
  • anonymous
16
anonymous
  • anonymous
by raising the square root to a power of 2, you pretty much undo it all so you're left with x+4=16
anonymous
  • anonymous
solve for x
anonymous
  • anonymous
12
anonymous
  • anonymous
@nigel305 , what do you think?
anonymous
  • anonymous
thanks lol
anonymous
  • anonymous
simplier
anonymous
  • anonymous
I need a medal since i help
anonymous
  • anonymous
sorry cant she was first

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