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anonymous
 one year ago
Solve this equation :)
anonymous
 one year ago
Solve this equation :)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439764528624:dw

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1is it \[\sqrt[3]{70  2x}  10 = 6\]

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1okay then add 10 on both sides.......

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1and also \[(\sqrt[x]{a})^x = a\]

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1so u got \[\sqrt[3]{70  2x} = 4\]

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1now \[(\sqrt[3]{70  2x})^3 = 4^3 \]

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1okay then 70  2x = 64

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1wht do u think .???whts the next step

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would that be extraneous or not?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wouldnt it be none extraneous?

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1plug x = 3 in main equation and see whether it satisfies or not`....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, it does:) I plugged it into the 702x=64 equation not the orginal one

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.1okay so its not extraneous
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