anonymous
  • anonymous
Solve this equation :)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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anonymous
  • anonymous
|dw:1439764528624:dw|
rishavraj
  • rishavraj
is it \[\sqrt[3]{70 - 2x} - 10 = -6\]
anonymous
  • anonymous
yes

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More answers

rishavraj
  • rishavraj
okay then add 10 on both sides.......
anonymous
  • anonymous
4
rishavraj
  • rishavraj
and also \[(\sqrt[x]{a})^x = a\]
rishavraj
  • rishavraj
so u got \[\sqrt[3]{70 - 2x} = 4\]
anonymous
  • anonymous
yes
rishavraj
  • rishavraj
now \[(\sqrt[3]{70 - 2x})^3 = 4^3 \]
anonymous
  • anonymous
ok i got 4^3=64
rishavraj
  • rishavraj
okay then 70 - 2x = 64
rishavraj
  • rishavraj
wht do u think .???whts the next step
anonymous
  • anonymous
subtract 70
rishavraj
  • rishavraj
yupp
anonymous
  • anonymous
-6 :)
rishavraj
  • rishavraj
i mean -2x = -6
anonymous
  • anonymous
x=3
anonymous
  • anonymous
Would that be extraneous or not?
rishavraj
  • rishavraj
yup :))
anonymous
  • anonymous
wouldnt it be none extraneous?
anonymous
  • anonymous
*non lol
rishavraj
  • rishavraj
plug x = 3 in main equation and see whether it satisfies or not`....
anonymous
  • anonymous
yes, it does:) I plugged it into the 70-2x=64 equation not the orginal one
rishavraj
  • rishavraj
okay so its not extraneous

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