anonymous
  • anonymous
1/7(B+35)3 linear equations
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@Leong
anonymous
  • anonymous
@ganeshie8
anonymous
  • anonymous
@LynFran

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More answers

anonymous
  • anonymous
@Leong
anonymous
  • anonymous
@mathway
anonymous
  • anonymous
@izuru
anonymous
  • anonymous
@mathstudent55
anonymous
  • anonymous
can you help me @RunawayGalaxy
anonymous
  • anonymous
Well you're not being too clear in the question you're asking here, do you want to solve for B ?
anonymous
  • anonymous
yes
mathstudent55
  • mathstudent55
I don't understand what the problem is. There is no equal sign, so this is not an equation. what do you need to do?
anonymous
  • anonymous
ohh so sorry =3
mathstudent55
  • mathstudent55
Ok. Let me write it again.
anonymous
  • anonymous
ok
mathstudent55
  • mathstudent55
Solve for B: \(\large \dfrac{1}{7}(B + 35) = 3\)
mathstudent55
  • mathstudent55
Is that the problem?
anonymous
  • anonymous
yes
mathstudent55
  • mathstudent55
Ok. You have a multiplication of 1/7 on the left side that we need to get rid of. To get rid of a multiplication, you multiply by its reciprocal. The reciprocal of 1/7 is 7, so we multiply both sides by 7. Can you do that and show what you get?
mathstudent55
  • mathstudent55
\(\large 7 \times \dfrac{1}{7}(B + 35) = 7 \times 3\) What do you get?
anonymous
  • anonymous
7b and 245
mathstudent55
  • mathstudent55
No. On the let side, what is 7 * 1/7? The whole idea of multiplying both sides by 7 is to get rid of 1/7 on the left side. What is 7 * 1/7?
anonymous
  • anonymous
1
mathstudent55
  • mathstudent55
|dw:1439771895851:dw|
mathstudent55
  • mathstudent55
Correct. That means on the left side, we only have now: \(\large B + 35\) On the right side, what is 7 * 3?
anonymous
  • anonymous
21
mathstudent55
  • mathstudent55
Correct. That means now we have \(\large B + 35 = 21\)
mathstudent55
  • mathstudent55
We want B alone, but we have B + 35 on the left side. Since plus 35 means add 35, we do the opposite to get rid of the +35. We subtract 35. We must do the same to both sides of an equation, so we subtract 35 from both sides of the equation. \(\large B + 35 - 35 = 21 - 35\) What do you get?
anonymous
  • anonymous
35-21=14 B=14
anonymous
  • anonymous
thanks. :)
anonymous
  • anonymous
-14
mathstudent55
  • mathstudent55
Be careful. The left side is correct. B + 35 - 35 is simply B. On the right side, you have 21 - 35, not 35 - 21. The answer is not B = 14
anonymous
  • anonymous
lol
mathstudent55
  • mathstudent55
Oh, I see. You got it. The answer is B = -14
anonymous
  • anonymous
Sorry I didn't help, stepped away from the computer
anonymous
  • anonymous
its fine took an hour to get help :P
mathstudent55
  • mathstudent55
Now we check the answer in the original equation to see if it is correct. We get B = -14 If we plugin -14 for B in the original equation, we must get a true statement. \(\dfrac{1}{7}(B + 35) = 3\) \(\dfrac{1}{7}(-14 + 35) = 3\) \(\dfrac{1}{7}(21) = 3\) \(3 = 3\) Since 3 = 3 is a true statement, our solution B = -14 is correct.

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