1/7(B+35)3 linear equations

- anonymous

1/7(B+35)3 linear equations

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- anonymous

@Leong

- anonymous

@ganeshie8

- anonymous

@LynFran

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## More answers

- anonymous

@Leong

- anonymous

@mathway

- anonymous

@izuru

- anonymous

@mathstudent55

- anonymous

can you help me @RunawayGalaxy

- anonymous

Well you're not being too clear in the question you're asking here, do you want to solve for B ?

- anonymous

yes

- mathstudent55

I don't understand what the problem is. There is no equal sign, so this is not an equation. what do you need to do?

- anonymous

ohh so sorry =3

- mathstudent55

Ok. Let me write it again.

- anonymous

ok

- mathstudent55

Solve for B:
\(\large \dfrac{1}{7}(B + 35) = 3\)

- mathstudent55

Is that the problem?

- anonymous

yes

- mathstudent55

Ok. You have a multiplication of 1/7 on the left side that we need to get rid of.
To get rid of a multiplication, you multiply by its reciprocal.
The reciprocal of 1/7 is 7, so we multiply both sides by 7.
Can you do that and show what you get?

- mathstudent55

\(\large 7 \times \dfrac{1}{7}(B + 35) = 7 \times 3\)
What do you get?

- anonymous

7b and 245

- mathstudent55

No.
On the let side, what is 7 * 1/7?
The whole idea of multiplying both sides by 7 is to get rid of 1/7 on the left side.
What is 7 * 1/7?

- anonymous

1

- mathstudent55

|dw:1439771895851:dw|

- mathstudent55

Correct.
That means on the left side, we only have now: \(\large B + 35\)
On the right side, what is 7 * 3?

- anonymous

21

- mathstudent55

Correct.
That means now we have
\(\large B + 35 = 21\)

- mathstudent55

We want B alone, but we have B + 35 on the left side. Since plus 35 means add 35, we do the opposite to get rid of the +35. We subtract 35. We must do the same to both sides of an equation, so we subtract 35 from both sides of the equation.
\(\large B + 35 - 35 = 21 - 35\)
What do you get?

- anonymous

35-21=14 B=14

- anonymous

thanks. :)

- anonymous

-14

- mathstudent55

Be careful.
The left side is correct. B + 35 - 35 is simply B.
On the right side, you have 21 - 35, not 35 - 21.
The answer is not B = 14

- anonymous

lol

- mathstudent55

Oh, I see. You got it.
The answer is B = -14

- anonymous

Sorry I didn't help, stepped away from the computer

- anonymous

its fine took an hour to get help :P

- mathstudent55

Now we check the answer in the original equation to see if it is correct.
We get B = -14
If we plugin -14 for B in the original equation, we must get a true statement.
\(\dfrac{1}{7}(B + 35) = 3\)
\(\dfrac{1}{7}(-14 + 35) = 3\)
\(\dfrac{1}{7}(21) = 3\)
\(3 = 3\)
Since 3 = 3 is a true statement, our solution B = -14 is correct.

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