1/7(B+35)3 linear equations

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1/7(B+35)3 linear equations

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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can you help me @RunawayGalaxy
Well you're not being too clear in the question you're asking here, do you want to solve for B ?
yes
I don't understand what the problem is. There is no equal sign, so this is not an equation. what do you need to do?
ohh so sorry =3
Ok. Let me write it again.
ok
Solve for B: \(\large \dfrac{1}{7}(B + 35) = 3\)
Is that the problem?
yes
Ok. You have a multiplication of 1/7 on the left side that we need to get rid of. To get rid of a multiplication, you multiply by its reciprocal. The reciprocal of 1/7 is 7, so we multiply both sides by 7. Can you do that and show what you get?
\(\large 7 \times \dfrac{1}{7}(B + 35) = 7 \times 3\) What do you get?
7b and 245
No. On the let side, what is 7 * 1/7? The whole idea of multiplying both sides by 7 is to get rid of 1/7 on the left side. What is 7 * 1/7?
1
|dw:1439771895851:dw|
Correct. That means on the left side, we only have now: \(\large B + 35\) On the right side, what is 7 * 3?
21
Correct. That means now we have \(\large B + 35 = 21\)
We want B alone, but we have B + 35 on the left side. Since plus 35 means add 35, we do the opposite to get rid of the +35. We subtract 35. We must do the same to both sides of an equation, so we subtract 35 from both sides of the equation. \(\large B + 35 - 35 = 21 - 35\) What do you get?
35-21=14 B=14
thanks. :)
-14
Be careful. The left side is correct. B + 35 - 35 is simply B. On the right side, you have 21 - 35, not 35 - 21. The answer is not B = 14
lol
Oh, I see. You got it. The answer is B = -14
Sorry I didn't help, stepped away from the computer
its fine took an hour to get help :P
Now we check the answer in the original equation to see if it is correct. We get B = -14 If we plugin -14 for B in the original equation, we must get a true statement. \(\dfrac{1}{7}(B + 35) = 3\) \(\dfrac{1}{7}(-14 + 35) = 3\) \(\dfrac{1}{7}(21) = 3\) \(3 = 3\) Since 3 = 3 is a true statement, our solution B = -14 is correct.

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