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anonymous
 one year ago
1/7(B+35)3 linear equations
anonymous
 one year ago
1/7(B+35)3 linear equations

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you help me @RunawayGalaxy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well you're not being too clear in the question you're asking here, do you want to solve for B ?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2I don't understand what the problem is. There is no equal sign, so this is not an equation. what do you need to do?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Ok. Let me write it again.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Solve for B: \(\large \dfrac{1}{7}(B + 35) = 3\)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Is that the problem?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Ok. You have a multiplication of 1/7 on the left side that we need to get rid of. To get rid of a multiplication, you multiply by its reciprocal. The reciprocal of 1/7 is 7, so we multiply both sides by 7. Can you do that and show what you get?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2\(\large 7 \times \dfrac{1}{7}(B + 35) = 7 \times 3\) What do you get?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2No. On the let side, what is 7 * 1/7? The whole idea of multiplying both sides by 7 is to get rid of 1/7 on the left side. What is 7 * 1/7?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439771895851:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Correct. That means on the left side, we only have now: \(\large B + 35\) On the right side, what is 7 * 3?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Correct. That means now we have \(\large B + 35 = 21\)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2We want B alone, but we have B + 35 on the left side. Since plus 35 means add 35, we do the opposite to get rid of the +35. We subtract 35. We must do the same to both sides of an equation, so we subtract 35 from both sides of the equation. \(\large B + 35  35 = 21  35\) What do you get?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Be careful. The left side is correct. B + 35  35 is simply B. On the right side, you have 21  35, not 35  21. The answer is not B = 14

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Oh, I see. You got it. The answer is B = 14

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry I didn't help, stepped away from the computer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its fine took an hour to get help :P

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Now we check the answer in the original equation to see if it is correct. We get B = 14 If we plugin 14 for B in the original equation, we must get a true statement. \(\dfrac{1}{7}(B + 35) = 3\) \(\dfrac{1}{7}(14 + 35) = 3\) \(\dfrac{1}{7}(21) = 3\) \(3 = 3\) Since 3 = 3 is a true statement, our solution B = 14 is correct.
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