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anonymous
 one year ago
Sigma Notation
anonymous
 one year ago
Sigma Notation

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=4}^{15} 4(3n)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=1}^{15} 4(3n)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439769637735:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439769669471:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1what are your thoughts?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1so, why are you thinking A? i need to know your thought process here in order to correct it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because it looks like an arithmetic sequence and i know that it uses the formula an=a1(n1)d

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1hmm, if it was arithmetic, then the difference between terms is constant 4 + (16) = 12 12 + (16) .. is not 36, is it?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1if its geometric, the common element is multiplied 4(3) = 12 12(3) = 36

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes. I wasn't looking at it like that, but I see your point now.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1we also know our index goes from 4 to 15 so that should help eliminate some options as well

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1but i think you have some of your options displayed incorrectly ...

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439770483912:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It means \[\sum_{n=4}^{15}\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1\Large helps magnify the test

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1\Huge is the zoomiest \[\Huge \sum_{n=start}^{end}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok :) Do you get what I wrote down now?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1we want to start at 4 and end at 15 right? ... but the only real option we have i believe you misprinted .. dw:1439770648146:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1with a geometric sequence, the series is represented as an exponent on the common ratio \[\Huge \sum_{n=start}^{end}a_1(r)^{n1}\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1agreed? if so, what is our solution?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That was how it was written on my math packet so idk

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1hmm, then somewhere there is a misprint. C is 'closest' we have to the right format; but we would want it to start at 4, not 1 \[\Huge \sum_{n=\color{red} 4}^{15}4(3)^{n1}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok isn't D saying that then?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the summation of 4 times negative 3 to the n minus 1 power, from n equals 4 to 15.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1no, 4 is not 4 on the a_1 part

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439770907174:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh! My mistake, there was no negative 4!

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1in that case, its fine lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439770953367:dw Is this the answer then?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1as long as thats not a negative four .. id agree :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have another, so I'll just post it in the open question section. K?
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