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anonymous
 one year ago
What is the value of n in the equation four left parenthesis three n plus two right parenthesis to the power of start fraction one over two end fraction end power minus five equals zero question mark
anonymous
 one year ago
What is the value of n in the equation four left parenthesis three n plus two right parenthesis to the power of start fraction one over two end fraction end power minus five equals zero question mark

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0can you draw out the problem? or post a screenshot?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0so this? \[\LARGE 4(3n+2)^{1/2}  5 = 0\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0what's the first step? Any idea?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no youre going to have to walk me through this one

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0ok to make things simpler a bit, I'm going to let x = 3n+2 and replace the "3n+2" with x \[\LARGE 4(3n+2)^{1/2}  5 = 0\] \[\LARGE 4x^{1/2}  5 = 0\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0what does that 1/2 power mean?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0it means "square root", right?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0so \[\LARGE 4x^{1/2}  5 = 0\] \[\LARGE 4\sqrt{x}  5 = 0\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0now try to isolate sqrt(x). Get sqrt(x) all by itself on one side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you'll have to add 5 to one side

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0yep, then what?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0well you have this \[\LARGE 4\sqrt{x} = 5\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0how would we move that 4 over

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0hint: undo the "4 times"

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0you divide both sides by 4 to undo the multiplication

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0\[\LARGE 4\sqrt{x} = 5\] \[\LARGE \sqrt{x} = \frac{5}{4}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0are you able to isolate x completely?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0square both sides

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0give it a try

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0don't be afraid to get it wrong

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.05/4 times 5/4 = ???

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0remember we let x = 3n+2

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0so if x = 25/16, then 3n+2 = 25/16

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0isolate n in 3n+2 = 25/16

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could you please hurry i have 3 more questions

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0when you solve for n, what did you get?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0what did you try so far

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just want you to walk me through it bc i dont know how

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0ok read this article and it might help out http://www.purplemath.com/modules/solvelin.htm let me know if it helps or not

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok well could you please continue

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0have a look at that article first

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0ok we can work on this when you get back

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i need to know the answer
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