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anonymous
 one year ago
Graph y=log 3(x+2)1. Then, find the domain/range
anonymous
 one year ago
Graph y=log 3(x+2)1. Then, find the domain/range

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what does "solve" mean in this context?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Whoops! Not solve. Just graph and find the domain/range

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2I would use a graphing calculator like desmos https://www.desmos.com/calculator to graph this out. You will have to use the change of base formula to make sure the expression is typed in properly you will have to type in log(x+2)/log(3)  1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok thanks :) Would the domain be all real numbers?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2why all real numbers?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2you should have this graph https://www.desmos.com/calculator/fs1pnhr9hx

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2the left side of the graph seems to hit a "wall" of some sort

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, now I do. And it does seem like that

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2it turns out that you cannot plug in 0 or negative numbers into a log function so x+2 has to be positive x+2 > 0 leads to x > ???

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2yeah x = 2 is your vertical asymptote. The graph does NOT touch the vertical asymptote. It only gets closer and closer and closer.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2solving x+2 > 0 for x gives x > 2, which is the domain

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, I see :) Now what about the range?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2the left side shoots off to negative infinity (very quickly) the right side slowly approaches positive infinity. it just keeps growing forever

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the range would be all real #'s or infinity

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2all real numbers I think you're thinking of this notation \(\Large (\infty,\infty)\)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2you're welcome
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