Factor x^2-12x+36-49y^2

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Factor x^2-12x+36-49y^2

Mathematics
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I have x^2+24x-49y^2 so far
\[a^2-b^2=\left( a+b \right)\left( a-b \right)\] \[x^2-12x+36-49y^2=\left( x-6 \right)^2-\left( 7y \right)^2=?\]
um x^2-12x-36-49y^2

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I'm lost
Hint: \[\Large (x-6)^2 - (7y)^2\] \[\Large ({\color{red}{x-6}})^2 - ({\color{blue}{7y}})^2\] \[\Large ({\color{red}{a}})^2 - ({\color{blue}{b}})^2 = ({\color{red}{a}}-{\color{blue}{b}})({\color{red}{a}}+{\color{blue}{b}})\]
\[\Large x^2 - 12x + 36 = (x-6)^2\] \[\Large 49y^2 = (7y)^2\]
Would that be all?
no there's one more step
Hit me :)
use the difference of squares rule to factor \[\Large (x-6)^2 - (7y)^2\]
(x-6)^2=x^-12x-36 right? (7y)^2=49y^2 right?
you're going backwards though
what I'm aiming for is to go from this \[\Large ({\color{red}{x-6}})^2 - ({\color{blue}{7y}})^2\] to this \[\Large ({\color{red}{x-6}}-{\color{blue}{7y}})({\color{red}{x-6}}+{\color{blue}{7y}})\] I used the difference of squares rule
it's like saying x^2 - 64 factors to (x-8)(x+8)
Oh!! I get it now haha :D Thank you!
np

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