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anonymous

  • one year ago

Factor x^2-12x+36-49y^2

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  1. anonymous
    • one year ago
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    I have x^2+24x-49y^2 so far

  2. anonymous
    • one year ago
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    \[a^2-b^2=\left( a+b \right)\left( a-b \right)\] \[x^2-12x+36-49y^2=\left( x-6 \right)^2-\left( 7y \right)^2=?\]

  3. anonymous
    • one year ago
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    um x^2-12x-36-49y^2

  4. anonymous
    • one year ago
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    I'm lost

  5. jim_thompson5910
    • one year ago
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    Hint: \[\Large (x-6)^2 - (7y)^2\] \[\Large ({\color{red}{x-6}})^2 - ({\color{blue}{7y}})^2\] \[\Large ({\color{red}{a}})^2 - ({\color{blue}{b}})^2 = ({\color{red}{a}}-{\color{blue}{b}})({\color{red}{a}}+{\color{blue}{b}})\]

  6. jim_thompson5910
    • one year ago
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    \[\Large x^2 - 12x + 36 = (x-6)^2\] \[\Large 49y^2 = (7y)^2\]

  7. anonymous
    • one year ago
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    Would that be all?

  8. jim_thompson5910
    • one year ago
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    no there's one more step

  9. anonymous
    • one year ago
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    Hit me :)

  10. jim_thompson5910
    • one year ago
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    use the difference of squares rule to factor \[\Large (x-6)^2 - (7y)^2\]

  11. anonymous
    • one year ago
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    (x-6)^2=x^-12x-36 right? (7y)^2=49y^2 right?

  12. jim_thompson5910
    • one year ago
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    you're going backwards though

  13. jim_thompson5910
    • one year ago
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    what I'm aiming for is to go from this \[\Large ({\color{red}{x-6}})^2 - ({\color{blue}{7y}})^2\] to this \[\Large ({\color{red}{x-6}}-{\color{blue}{7y}})({\color{red}{x-6}}+{\color{blue}{7y}})\] I used the difference of squares rule

  14. jim_thompson5910
    • one year ago
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    it's like saying x^2 - 64 factors to (x-8)(x+8)

  15. anonymous
    • one year ago
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    Oh!! I get it now haha :D Thank you!

  16. jim_thompson5910
    • one year ago
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    np

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