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anonymous
 one year ago
Can someone please help and explain this to me??
Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring.
−b b2 − 4ac 2a
Use the part of the quadratic formula that you chose above and find its value, given the following quadratic equation:
4x2 + 6x + 2 = 0
anonymous
 one year ago
Can someone please help and explain this to me?? Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. −b b2 − 4ac 2a Use the part of the quadratic formula that you chose above and find its value, given the following quadratic equation: 4x2 + 6x + 2 = 0

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1The part b^2  2ac is called the discriminant. If the discriminant is positive, the equation has 2 real solutions. If the discriminant equals zero, there is one real solution. If the discriminant is negative, there are no real solutions.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1i guess you meant 4ac ? right ?....^

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1LOL, yes, correct.

Jacob902
 one year ago
Best ResponseYou've already chosen the best response.0Solving quadratic equations using quadratic formula? Question 1 (Multiple Choice Worth 1 points) What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth? x ≈ −3.23 and x ≈ 0.23 x ≈ −2.72 and x ≈ −0.28 x ≈ 0.28 and x ≈ 2.72< x ≈ −0.23 and x ≈ 3.23 For this one i keep getting 2.73 and 0.28 but the answer isnt there soo i just picked can you tell me if im right? Question 2 (Multiple Choice Worth 1 points) How can you tell when a quadratic equation has no real solutions? when the radicand is negative< when b in the quadratic formula is greater than the radicand when the radicand equals zero when the radicand is not a perfect square For this one im almost positive its the answer i have the arrow pointed 2 but just want you to clarify it Question 3 (Multiple Choice Worth 1 points) For which value of x does the graph of y = 3x2 − 2x − 5 cross the xaxis? 5/3 −1 −2 3/5 For this one i just need help i have noo freaking clue how to do it... Question 4 (FillInTheBlank Worth 5 points) Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. −b b2 − 4ac 2a Use the part of the quadratic formula that you chose above and find its value given the following quadratic equation: 2x2 + 7x + 3 = 0 Numerical Answers Expected! Answer for Blank 1: Again this one i have no clue... Question 6 (Multiple Choice Worth 1 points) What are the exact solutions of x^2 = 4 −7x I thought it was x=7x+the square root of 33 divided by 2 i think im right but im not sure Anyone please help the major questions i need help with is 4 and 3 but please try to clarify if the one i think i know are right are right Thank you :) Follow 2 answers Report Abuse Answers Krishnamurthy Best Answer: 1). 4x^2 + 3 = 12x 4x^2 + 12x  3 = 0 x = (12 +/ sqrt 96)/8 x = (3 +/ sqrt 6)/2 x = 0.275255 x = 2.72474 Answer: x ≈ −2.72 and x ≈ −0.28 2). How can you tell when a quadratic equation has no real solutions? when the radicand is negative 3). For which value of x does the graph of y = 3x^2  2x  5 cross the xaxis? 1 4). Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. b^2  4ac 5). Use the part of the quadratic formula that you chose above and find its value given the following quadratic equation: 2x^2 + 7x + 3 = 0 b^2  4ac = 49  24 = 25 6). x^2 = 4  7x x^2 + 7x  4 = 0 x = (7 +/ sqrt 65)/2 Krishnamurthy · 3 years ago 0 Thumbs up 0 Thumbs down Comment Report Abuse Jeff Aaron 1. 4x^2 + 3 = 12x 4x^2 + 12x + 3 = 0 x = (12 +/ sqrt(12^2  4(4)(3))) / (2*4) x = (12 +/ sqrt(144  48)) / 8 x = (12 +/ sqrt(96)) / 8 x = (12 +/ sqrt(96)) / 8 x = 1.5 +/ sqrt(1.5) x =~ 0.28 or 2.72 2. How can you tell when a quadratic equation has no real solutions? When the discriminant is negative (assuming the coefficients are real). 3. 3x^2  2x  5 = 0 x = ((2) +/ sqrt((2)^2  4(3)(5))) / (2*3) x = (2 +/ sqrt(4 + 60)) / 6 x = (2 +/ sqrt(64)) / 6 x = (2 +/ 8) / 6 x = (10 or 6) / 6 x = 5/3 or 1 6. x^2 = 4  7x x^2 + 7x  4 = 0 x = (7 +/ sqrt(7^2  4(1)(4))) / (2*1) x = (7 +/ sqrt(49 + 16)) / 2 x = (7 +/ sqrt(65)) / 2 x = 3.5 +/ sqrt(16.25)
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