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anonymous

  • one year ago

-6x+5y=-2 10x+5y=30 Elimination

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  1. anonymous
    • one year ago
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    Steps Only Needed

  2. pooja195
    • one year ago
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    10 (-6x+5y=-2) 6 (10x+5y=3) Distribute I did this because we need to get the x's to cancel so this way a postive and a negative value of the same number will cancel out x

  3. pooja195
    • one year ago
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    |dw:1439781385417:dw|

  4. anonymous
    • one year ago
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    ok

  5. pooja195
    • one year ago
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    |dw:1439781428541:dw|

  6. anonymous
    • one year ago
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    I Dont Do The Steps Thats Why I Need Them

  7. pooja195
    • one year ago
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    These are the steps im not giving you the answers.

  8. anonymous
    • one year ago
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    Oh Ok

  9. pooja195
    • one year ago
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    \[\Huge~\rm~ \begin{bmatrix}-6x+5y=-2 \\10x+5y=30\end{bmatrix} \] \[\Huge~\rm~\begin{bmatrix}-30x+25y=-10 \\30x+15y=90\end{bmatrix} \]

  10. pooja195
    • one year ago
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    ^thats what you get after you distribute

  11. pooja195
    • one year ago
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    The x's cancel out \[\Huge~\rm~\begin{bmatrix}25y=-10 \\15y=90\end{bmatrix}\]

  12. pooja195
    • one year ago
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    add the numbers 25+15= ? -10+90=?

  13. anonymous
    • one year ago
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    40

  14. anonymous
    • one year ago
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    and

  15. anonymous
    • one year ago
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    80

  16. pooja195
    • one year ago
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    40y=80 We need to divide both sides because we want to isolate x 40/40=1 therefore y =1 so just y whats 80/40?

  17. anonymous
    • one year ago
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    2

  18. pooja195
    • one year ago
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    Therefore y=2 Now all we do is plug in 2 in place of y that into the equation 1 \[\huge~\rm~\mathrm30x+25(2) =-10\]

  19. anonymous
    • one year ago
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    CORRECT.

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