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anonymous
 one year ago
6x+5y=2
10x+5y=30
Elimination
anonymous
 one year ago
6x+5y=2 10x+5y=30 Elimination

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pooja195
 one year ago
Best ResponseYou've already chosen the best response.110 (6x+5y=2) 6 (10x+5y=3) Distribute I did this because we need to get the x's to cancel so this way a postive and a negative value of the same number will cancel out x

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439781385417:dw

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439781428541:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I Dont Do The Steps Thats Why I Need Them

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1These are the steps im not giving you the answers.

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1\[\Huge~\rm~ \begin{bmatrix}6x+5y=2 \\10x+5y=30\end{bmatrix} \] \[\Huge~\rm~\begin{bmatrix}30x+25y=10 \\30x+15y=90\end{bmatrix} \]

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1^thats what you get after you distribute

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1The x's cancel out \[\Huge~\rm~\begin{bmatrix}25y=10 \\15y=90\end{bmatrix}\]

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1add the numbers 25+15= ? 10+90=?

pooja195
 one year ago
Best ResponseYou've already chosen the best response.140y=80 We need to divide both sides because we want to isolate x 40/40=1 therefore y =1 so just y whats 80/40?

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1Therefore y=2 Now all we do is plug in 2 in place of y that into the equation 1 \[\huge~\rm~\mathrm30x+25(2) =10\]
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