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@poopsiedoodle Can you please help me?

Here's a suggestion.
Post one of the questions, and maybe someone will help you.

can you help me with a couple please?

Once again, post a question.

Do you have the figure?

sorry, i was taking the screenshot of it

No problem.
I assume you are learning trigonometry of right triangles.

yes. its one of the chapters in my online geometry course

Ok.
Here we go.

okay. thank you so much. I really appreciate this

thats correct. we only need BC

so would be using SOH CAH TOA?

Exactly.
For angle C, is BC adjacent or opposite?

I would say adjacent

Cosine??

Correct.
CAH : cos A = adj/hyp

Very good so far.

Wait. I read the problem wrong.

I'm really sorry, but let's look at it again.

So should i write about the equations?
like these: cosθ=adj/hyp
cosC=BC/AC
cosx=y/AC

so we need to completely restart??

It's still a SOH CAH TOA problem only a different one.

would they still be using cosine or would they go to tnagent?

tagent*

\(\tan x = \dfrac{opp}{adj} \)
\(\tan x = \dfrac{AB}{y} \)

Now we solve for AB, the distance between the shooting star and the Earth.

\(AB = y \tan x\)

thank you

Now you need to finish it.

You have to be careful with which side is opposite and which side is adjacent.

so would the adjacent be C?

alright. i changed it

|dw:1439784419738:dw|

Great, you got it!

so is that all? is that everything i was supposed to write?