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sebastiangonzagonza

  • one year ago

HI PLEASE SOMEONE HELP ME WITH SOME QUESTIONS FOR GEOMETRY

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  1. sebastiangonzagonza
    • one year ago
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    @poopsiedoodle Can you please help me?

  2. sebastiangonzagonza
    • one year ago
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    @hero

  3. mathstudent55
    • one year ago
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    Here's a suggestion. Post one of the questions, and maybe someone will help you.

  4. sebastiangonzagonza
    • one year ago
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    can you help me with a couple please?

  5. mathstudent55
    • one year ago
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    Once again, post a question.

  6. sebastiangonzagonza
    • one year ago
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    A shooting star forms a right triangle with the Earth and the Sun, as shown below: A scientist measures the angle x and the distance y between the Earth and the Sun. Using complete sentences, explain how the scientist can use only these two measurements to calculate the distance between the Earth and the shooting star.

  7. mathstudent55
    • one year ago
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    Do you have the figure?

  8. sebastiangonzagonza
    • one year ago
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  9. sebastiangonzagonza
    • one year ago
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    sorry, i was taking the screenshot of it

  10. mathstudent55
    • one year ago
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    No problem. I assume you are learning trigonometry of right triangles.

  11. sebastiangonzagonza
    • one year ago
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    yes. its one of the chapters in my online geometry course

  12. mathstudent55
    • one year ago
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    Ok. Here we go.

  13. sebastiangonzagonza
    • one year ago
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    okay. thank you so much. I really appreciate this

  14. mathstudent55
    • one year ago
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    In your figure, you see you have a right triangle with right angle B. The hypotenuse is AC, and that is the distance you want to find. Also, you know angle x, and you know y.

  15. mathstudent55
    • one year ago
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    In this triangle, the hypotenuse is AC. We already know that. We want to find this length. There are 2 legs in a right triangle. In our right triangle the legs are BC with known length y, and AB, whose length we don't know but are also not interested in.

  16. sebastiangonzagonza
    • one year ago
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    thats correct. we only need BC

  17. mathstudent55
    • one year ago
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    In a right triangle, to distinguish between the two legs, we call them the adjacent leg and the opposite leg. These terms for the legs are with reference to an acute angle of the right triangle. The angle we are using is angle C since we know its measure is x.

  18. sebastiangonzagonza
    • one year ago
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    so would be using SOH CAH TOA?

  19. mathstudent55
    • one year ago
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    Exactly. For angle C, is BC adjacent or opposite?

  20. sebastiangonzagonza
    • one year ago
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    I would say adjacent

  21. mathstudent55
    • one year ago
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    Correct. We are only interested in three things in this triangle. Known angle C (measuring x) Known adjacent leg BC (measuring y) Unknown hypotenuse AC

  22. mathstudent55
    • one year ago
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    Using SOH CAH TOA, which one of the trig functions sine, cosine, tangent, relates the adjacent leg to the hypotenuse?

  23. sebastiangonzagonza
    • one year ago
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    Cosine??

  24. mathstudent55
    • one year ago
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    Correct. CAH : cos A = adj/hyp

  25. mathstudent55
    • one year ago
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    We can write an equation using the cosine equation and our known and unknown info. \(\cos \theta = \dfrac{adj}{hyp} \) \(\cos C = \dfrac{BC}{AC} \) \(\cos x = \dfrac{y}{AC} \) Since x is known, cos x is also known. y is known, so the only unknown is AC, which can be solved for. \(AC = \dfrac{y}{\cos x} \)

  26. sebastiangonzagonza
    • one year ago
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    so how would i put this in a essay form? this is what i have so far: To measure the distance between the the Earth and the shooting star, the scientist would be using SOH CAH TOA. For this particular question, they would be using CAH or cosine. cos A = adjacent/hypotenuse.

  27. mathstudent55
    • one year ago
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    Very good so far.

  28. mathstudent55
    • one year ago
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    Wait. I read the problem wrong.

  29. mathstudent55
    • one year ago
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    I'm really sorry, but let's look at it again.

  30. sebastiangonzagonza
    • one year ago
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    So should i write about the equations? like these: cosθ=adj/hyp cosC=BC/AC cosx=y/AC

  31. sebastiangonzagonza
    • one year ago
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    so we need to completely restart??

  32. mathstudent55
    • one year ago
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    The distance the problem is asking for is the distance between the shooting start and the Earth. We need to find AB, not AC.

  33. mathstudent55
    • one year ago
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    It's still a SOH CAH TOA problem only a different one.

  34. sebastiangonzagonza
    • one year ago
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    would they still be using cosine or would they go to tnagent?

  35. sebastiangonzagonza
    • one year ago
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    tagent*

  36. mathstudent55
    • one year ago
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    Wow, I see that you're smart. We will be using the tangent. We have x, the angle measure, and we have y, the adjacent side. The unknown is AB. AB is the opposite leg. The function that relates the opposite and adjacent legs is the tangent. TOA: tan A = opp/adj

  37. mathstudent55
    • one year ago
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    \(\tan x = \dfrac{opp}{adj} \) \(\tan x = \dfrac{AB}{y} \)

  38. sebastiangonzagonza
    • one year ago
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    lol i try. but when i do it alone, i usually dont do too well.. so im just trying to finish out the course right now. at 12am. on my bedroom floor

  39. mathstudent55
    • one year ago
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    Now we solve for AB, the distance between the shooting star and the Earth.

  40. mathstudent55
    • one year ago
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    \(AB = y \tan x\)

  41. mathstudent55
    • one year ago
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    Since I started you off incorrectly, I did the following to make it up to you. I fixed your beginning of the answer. To calculate the distance between the the Earth and the shooting star, the scientist would be using SOH CAH TOA. For this particular question, he would be using TOA or tangent. tan A = opposite/adjacent.

  42. sebastiangonzagonza
    • one year ago
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    thank you

  43. mathstudent55
    • one year ago
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    Now you need to finish it.

  44. sebastiangonzagonza
    • one year ago
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    so here is what i have now, after correcting it: To measure the distance between the the Earth and the shooting star, the scientist would be using SOH CAH TOA. For this particular question, they would be using TOA or tangent. The equation would be opposite/adjacent so y/AB Now, you would solve for AB AB=y tan x

  45. mathstudent55
    • one year ago
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    You have to be careful with which side is opposite and which side is adjacent.

  46. sebastiangonzagonza
    • one year ago
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    so would the adjacent be C?

  47. mathstudent55
    • one year ago
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    To calculate the distance between the the Earth and the shooting star, the scientist would be using SOH CAH TOA. For this particular question, they would be using TOA or tangent. The equation would be opposite/adjacent so tan x = AB/y Now, you would solve for AB AB=y tan x

  48. mathstudent55
    • one year ago
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    Also, change "measure" to "calculate" The scientist is calculating the distance based on some measurements. He is not measuring the distance.

  49. sebastiangonzagonza
    • one year ago
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    alright. i changed it

  50. mathstudent55
    • one year ago
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    |dw:1439784419738:dw|

  51. mathstudent55
    • one year ago
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    Great, you got it!

  52. sebastiangonzagonza
    • one year ago
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    so is that all? is that everything i was supposed to write?

  53. sebastiangonzagonza
    • one year ago
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    @mathstudent55

  54. mathstudent55
    • one year ago
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    Yes. It looks good to me. You've explained how to calculate the distance from the shooting start to Earth.

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