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x^2/x-1 i think .

1/[(x-2) (x-1)]

so i should just write 1/[(x-2) (x-1)]

what proof can i give?

Nevermind you are right, the degree of the denoinator has to be greater than the numerator.

you don't need 2 in the numerator.
f(x) = 1 / [( x -2)(x-1) ]
is fine

yes sorry i misread it . its late :|

what proof do i have, like how can i know that putting a 1 in front will give me my answer

and no worries, thanks for helping me

for large x, the denominator grows to infinity.
and 1 / infinity gets close to zero

|dw:1439785307400:dw|

the x^2 term in the denominator goes to infinity much faster than the other terms

yes, you can leave out lines 3 and 4 since they repeat

thank you