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anonymous
 one year ago
Give an example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at, x = 2 and x = 1.
anonymous
 one year ago
Give an example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at, x = 2 and x = 1.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so i should just write 1/[(x2) (x1)]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0An example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at, x = 2 and x = 1. horizontal asymptote at y = 0 vertical asymptote at x = 2 and x = 1 meaning that id have to use (x2) as well as (x1) and using a one on top of the division would give me the result that i want, which is a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at, x = 2 and x = 1. 1/[(x2) (x1)]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what proof can i give?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nevermind you are right, the degree of the denoinator has to be greater than the numerator.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you don't need 2 in the numerator. f(x) = 1 / [( x 2)(x1) ] is fine

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes sorry i misread it . its late :

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what proof do i have, like how can i know that putting a 1 in front will give me my answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and no worries, thanks for helping me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for large x, the denominator grows to infinity. and 1 / infinity gets close to zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439785307400:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the x^2 term in the denominator goes to infinity much faster than the other terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0An example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at, x = 2 and x = 1. horizontal asymptote at y = 0 vertical asymptote at x = 2 and x = 1 meaning that id have to use (x2) as well as (x1) and using a one on top of the division would give me the result that i want, which is a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at, x = 2 and x = 1. The 1/infinity would be close to zero (horizontal asymptote at y = 0) 1/[(x2) (x1)] which equals to 1/(x^23x+2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jayzdd should i just leave it like that^?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, you can leave out lines 3 and 4 since they repeat
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