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tiffanymak1996

  • one year ago

Solve X. A triangle ABC, with point D on line AB and point E on line AC. Point F is the intersection of line DC and EB. Angle ACD = 10 Angle DCB = 70 Angle EBC = 60 Angle EAD = 20 Angle EDC = x These r the only information given. Many Thanks!

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  1. wolf1728
    • one year ago
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    Here's a graphic

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  2. imqwerty
    • one year ago
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    |dw:1439799280664:dw|

  3. sohailiftikhar
    • one year ago
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    yes wolfi done this already by telling the graph bro

  4. sohailiftikhar
    • one year ago
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    there is nothing to tell now

  5. wolf1728
    • one year ago
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    Angle ADC = 180 -20 -10 = 150 Degrees Angle CDB = 30 Degrees Angle B = 180 -20 -(10+70) = 80 Degrees Angle EBA = 20 Degrees Angle EFD = 360 -140 -150-20 = 50 Degrees = Angle CFB Well maybe I'll give this a rest now

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  6. tiffanymak1996
    • one year ago
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    @imqwerty but x is Angle EDC, not Angle ADC

  7. imqwerty
    • one year ago
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    oops :D sry i'll correct it

  8. tiffanymak1996
    • one year ago
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    thank you!

  9. tiffanymak1996
    • one year ago
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    @imqwerty i got everything you guys get, but i couldnt get EDC, that's why i'm asking it here. :P

  10. wolf1728
    • one year ago
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    Seems this is still unsolved. Let's see if this helps. Triangle ACB is isosceles side AC = side AB Triangle AEB is isosceles side AE = side EB Any ideas anyone?

  11. wolf1728
    • one year ago
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    Haven't given up yet. I redrew the graphic trying to be as accurate as possible. (All the angles were drawn as closely as possible to their posted values.)

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  12. amilapsn
    • one year ago
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    \[\href{ https:///www.duckware.com/tech/worldshardesteasygeometryproblem.html }{\Huge \cal Click ~Here!!}\]

  13. wolf1728
    • one year ago
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    Thanks for the answer.

  14. amilapsn
    • one year ago
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    Yw!

  15. amilapsn
    • one year ago
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    But I recommend you not to read that answer straight away. Have sometime to try it yourself.

  16. wolf1728
    • one year ago
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    amilspan I've worked on it long enough. I drew both of the graphics posted here.

  17. tiffanymak1996
    • one year ago
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    thanks guys! Really appreciate the effort.:)))

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