## tiffanymak1996 one year ago Solve X. A triangle ABC, with point D on line AB and point E on line AC. Point F is the intersection of line DC and EB. Angle ACD = 10 Angle DCB = 70 Angle EBC = 60 Angle EAD = 20 Angle EDC = x These r the only information given. Many Thanks!

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1. wolf1728

Here's a graphic

2. imqwerty

|dw:1439799280664:dw|

3. sohailiftikhar

yes wolfi done this already by telling the graph bro

4. sohailiftikhar

there is nothing to tell now

5. wolf1728

Angle ADC = 180 -20 -10 = 150 Degrees Angle CDB = 30 Degrees Angle B = 180 -20 -(10+70) = 80 Degrees Angle EBA = 20 Degrees Angle EFD = 360 -140 -150-20 = 50 Degrees = Angle CFB Well maybe I'll give this a rest now

6. tiffanymak1996

@imqwerty but x is Angle EDC, not Angle ADC

7. imqwerty

oops :D sry i'll correct it

8. tiffanymak1996

thank you!

9. tiffanymak1996

@imqwerty i got everything you guys get, but i couldnt get EDC, that's why i'm asking it here. :P

10. wolf1728

Seems this is still unsolved. Let's see if this helps. Triangle ACB is isosceles side AC = side AB Triangle AEB is isosceles side AE = side EB Any ideas anyone?

11. wolf1728

Haven't given up yet. I redrew the graphic trying to be as accurate as possible. (All the angles were drawn as closely as possible to their posted values.)

12. amilapsn

$\href{ https:///www.duckware.com/tech/worldshardesteasygeometryproblem.html }{\Huge \cal Click ~Here!!}$

13. wolf1728

14. amilapsn

Yw!

15. amilapsn

But I recommend you not to read that answer straight away. Have sometime to try it yourself.

16. wolf1728

amilspan I've worked on it long enough. I drew both of the graphics posted here.

17. tiffanymak1996

thanks guys! Really appreciate the effort.:)))