Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- 1018

find y' :
y=sin(x+y)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- 1018

find y' :
y=sin(x+y)

- jamiebookeater

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

You just have to differentiate both sides of the equation with respect to x
\[\frac{d}{dx}(y)=\frac{d}{dx}(\sin(x+y))\]
Left side becomes simply derivative of y with respect to x, for the right side u must use chain rule
Alternatively you can separate the variables
\[\sin^{-1}y=x+y\]
\[\sin^{-1}(y)-y=x\]
Either way you'll have to differentiate both sides of the equation, you can't just reduce the equation into a form of
\[y=f(x)\]
Such forms where you can't express y purely in terms of x are called as implicit,
and we use implicit differentiation, in this method we simply differentiate the whole equation with respect to the independent variable and re arrange the dy/dx term

- anonymous

Does that makes sense to you?

- 1018

may i ask, is it always with respect to x? it says i need y'

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

Generally it is with respect to x, most of the times you are required to find
\[y'=\frac{dy}{dx}\]
Besides think about it, your equation only has 2 variables, x and y, so you can only find derivative of y with respect to x or with respect to y,
derivative of y with respect to y would be 1 so that's kind of meaningless, so of course u have to find derivative of y with respect to x

- anonymous

Anyways, try differentiation both sides of equation with respect to x, let's see where this gets you to

- 1018

ok i think i got it. ill try again if my answer would be incorrect. thanks!

- anonymous

Ok show me your work once you've attempted the question

Looking for something else?

Not the answer you are looking for? Search for more explanations.