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anonymous
 one year ago
PLEASE HELP ME WRITE THE EQUATION FOR AN ELLIPSE: (MEDAL AND FAN!!!):
Write the equation of an ellipse with center (2,1); vertex (7,1) ; and focus (5,1).
anonymous
 one year ago
PLEASE HELP ME WRITE THE EQUATION FOR AN ELLIPSE: (MEDAL AND FAN!!!): Write the equation of an ellipse with center (2,1); vertex (7,1) ; and focus (5,1).

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439810883867:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok that makes sense, so how do I get a? I am just confused sorry.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439810946525:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2so it seems it is going to be a horizontal ellipse ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know that the equation is going to look like this: \[\frac{ (x2)^2 }{ ? } + \frac{ (y1)^2 }{ ? } = 1\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Right, center = \((h,k)=(2,1)\) we need to find the values of \(a,b\) and plug in : \[\dfrac{(x2)^2}{a^2}+\dfrac{(y1)^2}{b^2}=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just need a^2 and b^2...

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2use the vertex formula : \((h+a, k)=(7,1)\) can you find the value of \(a\) ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Correct. \(2+a=7\implies a=5\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Next use focus formula \((h+c,~k)=(5,1)\) can you find the value of \(c\) ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2\(h+c=5\) you know that \(h=2\), therefore \(c=?\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Yes, \(a=5,~c=3\) we still need to find \(b\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so I use this right: c^2 = b^2  a^2?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2it should be \(a^2 = b^2+c^2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whoops ok, sorry: 5^2 = 3^2 + b^2 25 = 9 + b^2 16 = b^2 b = 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so my final answer is: \[\frac{ (x2)^2}{ 25 } + \frac{ (y2)^2 }{ }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whoops i messed that up under the (y2)^2 is 16. and it all equals 1 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so now that i got that, how do I approach this when I am given center, covertex, and focus? Can i post the question?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Ok so my final answer is: \[\frac{ (x2)^2}{ 25 } + \frac{ (y\color{red}{1})^2 }{ \color{red}{16} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry that is what i meant, lol i had that written down...
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