anonymous
  • anonymous
Hey, I need help with one question about ellipses. I have to go so a simple step by step for the situation and then with my numbers to plug in would be good. Please help quickly... The question is: Write the equation of an ellipse with center (-3,2); covertex (-8,2) and focus (-3,-10)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Loser66
  • Loser66
What is the formula of a shifted ellipse?
anonymous
  • anonymous
\[\frac{ (x-h)^2 }{ a^2 } + \frac{ (y-k)^2 }{ b^2 } = 1\]?
Loser66
  • Loser66
Yup!! how to find the major vertices from foci and co-vertices?

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Loser66
  • Loser66
c^2=......
anonymous
  • anonymous
c^2 = a^2 - b^2
Loser66
  • Loser66
Yes, you have foci c, and b, how to find a^2?
anonymous
  • anonymous
what what is c? is it -3?
anonymous
  • anonymous
sorry you kind of lost me...
Loser66
  • Loser66
no no, I am just asking about the formula, not number yet.
anonymous
  • anonymous
oh ok. I think to find a^2 you turn it around so it is: a^2 = b^2 = c^2? or is it a completely different formula
Loser66
  • Loser66
ok, now, draw out the given points.
anonymous
  • anonymous
|dw:1439814717542:dw|
Loser66
  • Loser66
|dw:1439814693102:dw|
anonymous
  • anonymous
5 units
Loser66
  • Loser66
yes, so from the center, go to the right 5 units, what is the other co-vertex?
anonymous
  • anonymous
2,2?
Loser66
  • Loser66
yes, again
Loser66
  • Loser66
|dw:1439814820325:dw|
anonymous
  • anonymous
8 units
Loser66
  • Loser66
nope
anonymous
  • anonymous
oh lol 12 sorry i wasn't thinking
Loser66
  • Loser66
ok, that is c, and b is 5 hence a^2=?
anonymous
  • anonymous
a^2 = 5^2 + 12^2 a^2 = 25 + 144 a^2 = 169
Loser66
  • Loser66
ok, a =?
anonymous
  • anonymous
13
Loser66
  • Loser66
plug them into the standard equation.
anonymous
  • anonymous
I get this: \[\frac{ (x+3)^2 }{ 25 } + \frac{ (y-2)^2 }{ 169 } = 1\]
anonymous
  • anonymous
is that right?
misty1212
  • misty1212
looks good to me!

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