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anonymous

  • one year ago

Hey, I need help with one question about ellipses. I have to go so a simple step by step for the situation and then with my numbers to plug in would be good. Please help quickly... The question is: Write the equation of an ellipse with center (-3,2); covertex (-8,2) and focus (-3,-10)

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  1. Loser66
    • one year ago
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    What is the formula of a shifted ellipse?

  2. anonymous
    • one year ago
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    \[\frac{ (x-h)^2 }{ a^2 } + \frac{ (y-k)^2 }{ b^2 } = 1\]?

  3. Loser66
    • one year ago
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    Yup!! how to find the major vertices from foci and co-vertices?

  4. Loser66
    • one year ago
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    c^2=......

  5. anonymous
    • one year ago
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    c^2 = a^2 - b^2

  6. Loser66
    • one year ago
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    Yes, you have foci c, and b, how to find a^2?

  7. anonymous
    • one year ago
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    what what is c? is it -3?

  8. anonymous
    • one year ago
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    sorry you kind of lost me...

  9. Loser66
    • one year ago
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    no no, I am just asking about the formula, not number yet.

  10. anonymous
    • one year ago
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    oh ok. I think to find a^2 you turn it around so it is: a^2 = b^2 = c^2? or is it a completely different formula

  11. Loser66
    • one year ago
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    ok, now, draw out the given points.

  12. anonymous
    • one year ago
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    |dw:1439814717542:dw|

  13. Loser66
    • one year ago
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    |dw:1439814693102:dw|

  14. anonymous
    • one year ago
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    5 units

  15. Loser66
    • one year ago
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    yes, so from the center, go to the right 5 units, what is the other co-vertex?

  16. anonymous
    • one year ago
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    2,2?

  17. Loser66
    • one year ago
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    yes, again

  18. Loser66
    • one year ago
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    |dw:1439814820325:dw|

  19. anonymous
    • one year ago
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    8 units

  20. Loser66
    • one year ago
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    nope

  21. anonymous
    • one year ago
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    oh lol 12 sorry i wasn't thinking

  22. Loser66
    • one year ago
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    ok, that is c, and b is 5 hence a^2=?

  23. anonymous
    • one year ago
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    a^2 = 5^2 + 12^2 a^2 = 25 + 144 a^2 = 169

  24. Loser66
    • one year ago
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    ok, a =?

  25. anonymous
    • one year ago
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    13

  26. Loser66
    • one year ago
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    plug them into the standard equation.

  27. anonymous
    • one year ago
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    I get this: \[\frac{ (x+3)^2 }{ 25 } + \frac{ (y-2)^2 }{ 169 } = 1\]

  28. anonymous
    • one year ago
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    is that right?

  29. misty1212
    • one year ago
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    looks good to me!

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