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Since I already know the diameter of the original tube which is 5.0cm, The area of the circle is calculated by (3.14)(2.5)^2=19.625cm^2 On the other hand the area of the second tube where the diameter is decreased from 5.0cm to 2.cm the area is (3.14)(1.00)^2=3.14cm^2 Therefore assuming that equation of continuity holds true in this situation 10m/s*(19.625cm^2/3.1cm^2)=10m/s*6.330=63.30m/s^2 Adjusting for sig figs of 1, Therefore velocity of the water increased from 10m/s^2 to 60m/s^2 .
Please see if my solution is well reasoned according to the principles of continuity equation. Thanks!
Oh by the way this is hydraulics and pneumatics
Just so you know I am not big on those
In my honest opinion this line of reasoning seems pretty sound to me.
Looks good to me :) And your reasoning sounds pretty good also. Great Job :)
Oh yeah you think? I trust you buddy
Yeah I think it looks pretty good :)
blah I'm kind of horrible at Physics :( and it's almost 3:30 am , so my mind needs to go zzz zzz
Thanks for your try though !
Water behaves like air does... But some properties are so different that water is used as multiplier of force.
Did you learn about hydrostatic paradox?
no... I'm more geared towards the general computational math and pure math. So, anything to do with Science, I will run real fast . ^_^
If you combine your brain and my brain it will be well balanced
I am like screw-math-science-rocks kinda guy so