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Mindblast3r

  • one year ago

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  1. mindblast3r
    • one year ago
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    \[r^2=\frac{ 9 }{ 2 }\]

  2. mindblast3r
    • one year ago
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    \[r=\frac{ 3\sqrt2 }{ 2 }\]

  3. mindblast3r
    • one year ago
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    How did 9 become,

  4. mindblast3r
    • one year ago
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    \[3\sqrt2\]

  5. Nnesha
    • one year ago
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    got it okay so you have to take square root both sides to cancel out the square

  6. Nnesha
    • one year ago
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    \[\huge\rm \sqrt{r^2}=\sqrt{\frac{ 9 }{ 2 }}\] square root both sides

  7. Nnesha
    • one year ago
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    \[\sqrt{r^2} = r \] square root cancels with the square because when you convert square root to exponent you will get \[\huge\rm \sqrt{r^2} = r^\frac{ \cancel{2} }{\cancel{ 2} }\] according to this exponent rule \[\large\rm \sqrt[n]{x^m} = x^\frac{ m }{ n }\]

  8. Nnesha
    • one year ago
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    now solve right side \[\sqrt{\frac{ 9 }{ 2 }}\] is same as square root of 9 and 2 \[\sqrt{\frac{ 9 }{ 2 }}=\frac{ \sqrt{9} }{ \sqrt{2} }\] you can't have the radical sign at the denominator of the fraction so that's why multiply both the denominator and numerator of the fraction by sqrt{2}(denominator)

  9. mindblast3r
    • one year ago
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    ohh right i get it now!

  10. Nnesha
    • one year ago
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    (multiply top and bottom of the fraction by the denominator which is sqrt{2}_

  11. Nnesha
    • one year ago
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    u sure ? :)

  12. mindblast3r
    • one year ago
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    yes let me show you.

  13. Nnesha
    • one year ago
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    okay :)

  14. mindblast3r
    • one year ago
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    \[\sqrt{r^2} =\frac{ \sqrt9 }{ \sqrt2 }\]

  15. mindblast3r
    • one year ago
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    sec

  16. mindblast3r
    • one year ago
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    \[r=\frac{ 3 }{ \sqrt2^\frac{ 1 }{ 2 } }\times \frac{ \sqrt2 }{ \sqrt2\frac{ 1 }{ 2 } }\]

  17. mindblast3r
    • one year ago
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    \[r=\frac{ 3\sqrt2 }{ 2 }\]

  18. Nnesha
    • one year ago
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    so why did you write sqr{2} to the 1/2 power ?

  19. mindblast3r
    • one year ago
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    are you testing me, or you don't know why?

  20. Nnesha
    • one year ago
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    hahah i'm asking a question :)

  21. Nnesha
    • one year ago
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    actually i don't know why did you write square root AND 1/2 power

  22. mindblast3r
    • one year ago
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    i actually don't know how it works..

  23. mindblast3r
    • one year ago
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    but i know it's correct.

  24. Nnesha
    • one year ago
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    no \[\huge\rm \sqrt{x} = x^\frac{ 1 }{ 2 }\] 1/2 is same as square root of something

  25. Nnesha
    • one year ago
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    you can write \[\frac{ }{ 2^\frac{ 1 }{ 2 } \times 2^\frac{ 1 }{ 2 }}\] then you don't need to write square root

  26. mindblast3r
    • one year ago
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    hmm

  27. mindblast3r
    • one year ago
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    w8 w8 w8

  28. mindblast3r
    • one year ago
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    i remember who told me this i will link you to the question.

  29. Nnesha
    • one year ago
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    don't get it ? it's okay so this is the exponent rule \[\sqrt[n]{x^m}=x^\frac{m }{ n}\]

  30. mindblast3r
    • one year ago
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    oh wait i think i get it

  31. Nnesha
    • one year ago
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    so square root of sqrt{2} is 2^1/2 power \[\huge\rm \sqrt{2} = 2^\frac{ 1 }{ 2 }\] when you changed to exponent form then you don't need square root

  32. mindblast3r
    • one year ago
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    oh right!! you are right lol.

  33. mindblast3r
    • one year ago
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    the guy told me the same thing you're telling me now! sorry!!!!

  34. Nnesha
    • one year ago
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    ye same thing \[\sqrt{3}=3^\frac{ 1 }{ 3 }\]

  35. Nnesha
    • one year ago
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    it's okay :)

  36. mindblast3r
    • one year ago
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    1/3? you mean 1/2?

  37. Nnesha
    • one year ago
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    2 i did type 2 or is it 3 o.O

  38. mindblast3r
    • one year ago
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    its 3 lol.

  39. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Nnesha ye same thing \[\sqrt{3}=3^\frac{ 1 }{ 3 }\] \(\color{blue}{\text{End of Quote}}\) \[\huge\rm \sqrt{3}=3^\frac{ 1 }{ 3 }\] ohh i see now yea i meant 2 :)

  40. mindblast3r
    • one year ago
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    lol ok thanks!

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