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anonymous

  • one year ago

how is the expression log32-log8 written as a single logarithm?

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  1. JoannaBlackwelder
    • one year ago
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    Use this rule:|dw:1439832716851:dw|

  2. anonymous
    • one year ago
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    log(4)

  3. JoannaBlackwelder
    • one year ago
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    @Mayonnayse Can you use the formula I gave to rewrite your expression?

  4. anonymous
    • one year ago
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    Yes, but what does the b, m and n stand for?

  5. JoannaBlackwelder
    • one year ago
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    b is the base of the log, m and n are what you are taking the log of.

  6. JoannaBlackwelder
    • one year ago
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    When the base isn't written, it is assumed to be 10

  7. anonymous
    • one year ago
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    Oh ok

  8. anonymous
    • one year ago
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    Sure i can write it now. Log10(32)-log10(8)=log32/8

  9. anonymous
    • one year ago
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    Which is Log4?

  10. JoannaBlackwelder
    • one year ago
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    Yep, great! :-)

  11. anonymous
    • one year ago
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    Awesome! Thank you very much

  12. JoannaBlackwelder
    • one year ago
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    You're welcome

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