how is the expression log32-log8 written as a single logarithm?

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how is the expression log32-log8 written as a single logarithm?

Mathematics
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Use this rule:|dw:1439832716851:dw|
log(4)
@Mayonnayse Can you use the formula I gave to rewrite your expression?

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Yes, but what does the b, m and n stand for?
b is the base of the log, m and n are what you are taking the log of.
When the base isn't written, it is assumed to be 10
Oh ok
Sure i can write it now. Log10(32)-log10(8)=log32/8
Which is Log4?
Yep, great! :-)
Awesome! Thank you very much
You're welcome

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