There are K people in a room, each person picks a day of the year to get a free dinner at a fancy restaurant.K is such that there must be at least one group of six people who select the same day. What is the smallest such K if the year is a leap year (366days)?
(a) 1829 (b) 1831 (c) 1830 (d) 1832 (e) 1833. Answer is c.please explain how

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According to me it is 366*5=1830 but how 1831

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