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angiepangie0726
 one year ago
I really need some help :(
angiepangie0726
 one year ago
I really need some help :(

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angiepangie0726
 one year ago
Best ResponseYou've already chosen the best response.0The function f(x) = 4(3)x represents the growth of a dragonfly population every year in a remote swamp. Erin wants to manipulate the formula to an equivalent form that calculates four times a year, not just once a year. Which function is correct for Erin's purpose, and what is the new growth rate?

angiepangie0726
 one year ago
Best ResponseYou've already chosen the best response.0Do you think you can help me out? @juliastevens

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0As much as i would love two, im not good at that kind of math, im very sorry.

angiepangie0726
 one year ago
Best ResponseYou've already chosen the best response.0do you know anyone who could?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know which number in the formula represents the growth rate?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right, so if it's 3 for the whole year, divide it by 4 to get the growth rate every quarter

angiepangie0726
 one year ago
Best ResponseYou've already chosen the best response.0these are my choices f(x) = 4(3)x; growth rate 300% f(x) = 4(3)x, growth rate 4% f(x) = 4(1.32)x; growth rate 4% f(x) = 4(1.32)4x; growth rate 32%

angiepangie0726
 one year ago
Best ResponseYou've already chosen the best response.0would it be b?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0@angiepangie0726 Is the formula an exponential? If it is you need to put the ^ sign to show that it is an exponential function. f(x)=4(3^x) is the same as \(f(x)=4(3^x)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nvm. I think the growth rate is 2 on the year. I think the formula's something like a(1 +r)^x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not at all sure about this anymore. talked myself in circles :/
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