anonymous
  • anonymous
Use the functions m(x) = 5x + 4 and n(x) = 6x − 9 to complete the function operations listed below. Part A: Find (m + n)(x). Show your work. (3 points) Part B: Find (m ⋅ n)(x). Show your work. (3 points) Part C: Find m[n(x)]. Show your work. (4 points)
Mathematics
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anonymous
  • anonymous
Use the functions m(x) = 5x + 4 and n(x) = 6x − 9 to complete the function operations listed below. Part A: Find (m + n)(x). Show your work. (3 points) Part B: Find (m ⋅ n)(x). Show your work. (3 points) Part C: Find m[n(x)]. Show your work. (4 points)
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Help fan and medal plz
NathalyN
  • NathalyN
Well, do you know the process in general for this sort of thing?
anonymous
  • anonymous
Nope I am bad at math ._.

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NathalyN
  • NathalyN
Well, function composition is mainly an exercise in writing things out properly, then simplifying. If I said simplify x + 2 + x + 5 it is pretty obvious it is 2x + 7. But if I say f(x)= x + 2 and g(x) = x + 5 then ask "What is (f + g)(x)?" it is less obvious, but it is the same thing. It just means you write out some more steps: (f + g)(x) = f(x) + g(x) (f + g)(x) = (x + 2) + (x + 5) (f + g)(x) = x + 2 + x + 5 (f + g)(x) = 2x + 7 That shows the steps, basically. Do similar things with your functions.
anonymous
  • anonymous
Ok so that is the same thing for Part B and A?
NathalyN
  • NathalyN
b is multiply. c is function inside a function. So you replace x in the outter function with the entore inner. So to take my example, f[g(x)] means I do this: x+2 (x+5)+2 x+7 I am putting the x+5 inside the x+2 in place of the x. So again, just use your functions and do the same thing.
anonymous
  • anonymous
Ok thanks

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