probability question

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\(\large \color{black}{\begin{align} & \normalsize \text{Probability of solving specific problem independently by A and B are}\hspace{.33em}\\~\\ & \dfrac12\ \ \normalsize \text{and}\ \ \dfrac13\ \normalsize \text{respectively.}\hspace{.33em}\\~\\ & \normalsize \text{If both try to solve the problem independently, find the probability}\hspace{.33em}\\~\\ & \normalsize \text{ that exactly one of them solves the problem.}\hspace{.33em}\\~\\ \end{align}}\)
you want to find below two probabilities and then add them : 1) A solves the problem but B doesn't 2) A doesn't solve the problem but B solves it
P("A solves" AND "B doesnt solve") = ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

how did u know i need to find this 1) A solves the problem but B doesn't 2) A doesn't solve the problem but B solves it
good question, thats because of the phrase "exactly one of them"
"exactly one of them" means only one of them solves the problem
ok
P("A solves" AND "B doesnt solve") = P(A\(\cap\)B')
is this correct P("A solves" AND "B doesnt solve") = P(A∩B')
  • phi
yes
Correct, it is easy, go ahead and find it...
P(A∩B')=P(A)-P(A∩B)
i suggest you not use the formulas to solve these problems, use the problem to make sense of formulas instead
There are only four situations. 1. A solves it and B couldn't. 2. A couldn't solve it and B solves it. 3. A and B both solve it. 4. A and B both couldn't solve it (idiots!) The question is asking for the probability of exactly one of them solves it (or one of them is an idiot!), so it is asking for the probability of 1 or 2 happening.
how can i solve it without formula "P(A∩B')"
you're given, probability that B solves the problem = 1/3 so can you guess the probability that B couldn't solve the problem ?
the probability that B couldn't solve the problem=2/3
I think it is true for all events X, P(X')=1-P(X).
Yes, since the events are independent, simply multiply the probabilities : P("A solves" AND "B doesnt solve") = P("A solves")*P("B doesnt solve") = ?
the probability that B couldn't solve the problem =1/2*2/3=1/3
Put it in another way, an event can either happen or not happen. No event can not happen and not not happen at the same time.
Correct. try finding the probability for other case too : 2) A doesn't solve the problem but B solves it
P("A doesnt solves" AND "B does solve") =1/6
Add them up and you're done!
=1/2
1/3 + 1/6 = 3/6 yeah 1/2 looks good to me
thnx

Not the answer you are looking for?

Search for more explanations.

Ask your own question