At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

P("A solves" AND "B doesnt solve") = ?

good question, thats because of the phrase "exactly one of them"

"exactly one of them"
means
only one of them solves the problem

ok

P("A solves" AND "B doesnt solve") = P(A\(\cap\)B')

is this correct P("A solves" AND "B doesnt solve") = P(A∩B')

yes

Correct, it is easy, go ahead and find it...

P(A∩B')=P(A)-P(A∩B)

how can i solve it without formula "P(A∩B')"

the probability that B couldn't solve the problem=2/3

I think it is true for all events X, P(X')=1-P(X).

the probability that B couldn't solve the problem =1/2*2/3=1/3

P("A doesnt solves" AND "B does solve") =1/6

Add them up and you're done!

=1/2

1/3 + 1/6 = 3/6
yeah 1/2 looks good to me

thnx