## anonymous one year ago What value of k solves the equation? k^-5=1/32

1. anonymous

$\frac{1}{k^5}=\frac{1}{32}\iff k^5=32$

2. anonymous

think of a number that, when raised to the power of 5, gives 32

3. anonymous

2?

4. anonymous

if it not obvious, make a guess yes $$k=2$$ because $$2^5=32$$

5. anonymous

Thank you!

6. anonymous

yw