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anonymous
 one year ago
Solve the following system of equations and show all work.
y = x2 + 3
y = x + 5
anonymous
 one year ago
Solve the following system of equations and show all work. y = x2 + 3 y = x + 5

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iPwnBunnies
 one year ago
Best ResponseYou've already chosen the best response.0I think the easiest way is to equate the x part to each other (since y = y), bring all the terms to one side, and solve the quadratic equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok that makes sense, but now what?

iPwnBunnies
 one year ago
Best ResponseYou've already chosen the best response.0Take all the terms to the right side, so the left side becomes 0.

iPwnBunnies
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, like that. Although, it might've been easier to put the left part on the right side, so you won't have a negative x^2 term. But it makes no difference. If you multiply both sides by 1, you'll get the nicer form. Do that, and simplify.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait I'm confused, can you show me?

iPwnBunnies
 one year ago
Best ResponseYou've already chosen the best response.00 = x^2 + 3  x  5

iPwnBunnies
 one year ago
Best ResponseYou've already chosen the best response.0X and 5 are both positive on the left side, so when you subtract it, it'll be negative on the right side.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok got it, no combine 3 and 5 ?

iPwnBunnies
 one year ago
Best ResponseYou've already chosen the best response.0Exactly! Finally, solve the quadratic equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0available to help with one more?

iPwnBunnies
 one year ago
Best ResponseYou've already chosen the best response.0I can't find now unfortunately. I'm sorry :c But good luck!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait can you show me the equation real quick with 3 and 5 combined?
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