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DanielaJohana
 one year ago
use trigonometric identities to simplify:
(csc(x)tan(x))sin(x)cos(x)
DanielaJohana
 one year ago
use trigonometric identities to simplify: (csc(x)tan(x))sin(x)cos(x)

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0write csc and tan in terms of sin and cos

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0csc =?? tan= ?? what is reciprocal of tan and csc ?

DanielaJohana
 one year ago
Best ResponseYou've already chosen the best response.0reciprocal of tanx is 1/cotx reciprocal of cscx is 1/sinx ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right and also tan = sin over cos \[\huge\rm [\color{red}{\csc(x)\tan(x)}]\sin(x)\cos(x)\] \[(\color{Red}{\frac{ 1 }{ \sin(x)} \frac{ \sin(x) }{ \cos(x) }})\sin(x)\cos(x)\] now solve the parentheses find common denomiantor

DanielaJohana
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha So the common denom would be sin(x)cos(x) right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[(\color{Red}{\frac{ ???? }{ \sin(x)cos(x)} })\sin(x)\cos(x)\] multiply top of first fraction by the bottom of the 2nd fraction multiply numerator of 2nd fraction by denominator of first fraction \[(\color{Red}{\frac{ 1(cos(x))sin(x)sin(x) }{ \sin(x)cos(x)} })\sin(x)\cos(x)\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0try to simplify tht from there

DanielaJohana
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha Would I cancel the denominator with the outside?

DanielaJohana
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha so would my final answer be \[\cos(x)\sin^{2}(x)\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0you can simplify that sin^2 = ? btw do you have options ?

DanielaJohana
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha no I don't \[\sin ^{2}x = \frac{ 1\cos2(x) }{ 2 }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0sin^2x is just equal to 1cos^2\[\rm cos^2 \theta +\sin^2 \theta =1\] so when you solve for sin^2theat you will get 1cos^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0but i don't think we should substitute sin^2 just leave it as cos(x)sin^2(x)

DanielaJohana
 one year ago
Best ResponseYou've already chosen the best response.0oh okay then thanks
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