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anonymous
 one year ago
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A circle is centered at (−3, 2) and has a radius of 2. Which of the following is the equation for this circle?
(x + 3)2 + (y − 2)2 = 2
(x − 3)2 + (y + 2)2 = 4
(x + 3)2 + (y − 2)2 = 4
(x − 3)2 + (y + 2)2 = 2
anonymous
 one year ago
Need help! Will fan and medal!! A circle is centered at (−3, 2) and has a radius of 2. Which of the following is the equation for this circle? (x + 3)2 + (y − 2)2 = 2 (x − 3)2 + (y + 2)2 = 4 (x + 3)2 + (y − 2)2 = 4 (x − 3)2 + (y + 2)2 = 2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@sourwing @jrx120637 @mathstudent55 @surjithayer @prowrestler

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[if~ centre~ of~ circle ~is~\left( h,k \right)\] then eq. of circle is \[\left( xh \right)^2+\left( yk \right)^2=r^2\] where r is the radius of circle.
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