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anonymous
 one year ago
Solve 2x2 + x = 15.
x = −5 and x = 5
x = three over two and x = −5
x = 15 and x = −2
x = five over two and x = −3
anonymous
 one year ago
Solve 2x2 + x = 15. x = −5 and x = 5 x = three over two and x = −5 x = 15 and x = −2 x = five over two and x = −3

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Those aren't answers?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0to solve this, rewrite it \[2x^2 + x  15 = 0\] this can be factored or solved using the general quadratic formula for a quadratic \[ax^2 + bx + c = 0\] multiply a and c so you have 2 * 15 = 30 find the factors that add to 1, the larger factor is positive, so 6 and 5 next write it in factored form (ax + factor 1)(ax + factor 2)  a so your problem becomes \[\frac{(2x + 6)(2x  5)}{2} = 0\] remove any common factors \[\frac{2(x +3)(2x 5)}{2} = (x+3)(2x 5) = 0\] so you can solve x + 3 = 0 and 2x  5 = 0 to get the solutions
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