Solve 2x2 + x = 15. x = −5 and x = 5 x = three over two and x = −5 x = 15 and x = −2 x = five over two and x = −3

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Solve 2x2 + x = 15. x = −5 and x = 5 x = three over two and x = −5 x = 15 and x = −2 x = five over two and x = −3

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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-3 and 2.5
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to solve this, rewrite it \[2x^2 + x - 15 = 0\] this can be factored or solved using the general quadratic formula for a quadratic \[ax^2 + bx + c = 0\] multiply a and c so you have 2 * -15 = -30 find the factors that add to 1, the larger factor is positive, so 6 and -5 next write it in factored form (ax + factor 1)(ax + factor 2) ------------------------- a so your problem becomes \[\frac{(2x + 6)(2x - 5)}{2} = 0\] remove any common factors \[\frac{2(x +3)(2x -5)}{2} = (x+3)(2x -5) = 0\] so you can solve x + 3 = 0 and 2x - 5 = 0 to get the solutions

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