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anonymous

  • one year ago

Need help! Will fan and medal!! A circle is centered at (−3, 2) and has a radius of 2. Which of the following is the equation for this circle? (x + 3)2 + (y − 2)2 = 2 (x − 3)2 + (y + 2)2 = 4 (x + 3)2 + (y − 2)2 = 4 (x − 3)2 + (y + 2)2 = 2

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  1. anonymous
    • one year ago
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    @prowrestler @keshaun455 @mathstudent55 @itsmichelle29 @lizzieeej @vlz6000 @campbell_st

  2. campbell_st
    • one year ago
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    well the general form of a circle is \[(x - h)^2 + (y - k)^2 = r^2\] the centre is (h, k) and r is the radius so substitute your information and get a solution.

  3. anonymous
    • one year ago
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    What numbers exactly would i be substituting @campbell_st

  4. campbell_st
    • one year ago
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    well you are told the centre is (-3, 2) and radius is 2 so h = -3 k = 2 and r = 2

  5. anonymous
    • one year ago
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    soo (x-3)2+ (y-2)2=4? @campbell_st

  6. campbell_st
    • one year ago
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    no (x - (-3))^2 + (y -2)^2 = 2^2 simplify the 1st term

  7. anonymous
    • one year ago
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    What 1st term?? I'm so confused @campbell_st

  8. anonymous
    • one year ago
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    Would the answer be B then?

  9. anonymous
    • one year ago
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    @k_lynn @campbell_st

  10. campbell_st
    • one year ago
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    the answer isn't B.. just substitute correctly h = - 3 so (x - h) = ( x -(-3) which becomes (x + 3)

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