Need help! Will fan and medal!! A circle is centered at (−3, 2) and has a radius of 2. Which of the following is the equation for this circle? (x + 3)2 + (y − 2)2 = 2 (x − 3)2 + (y + 2)2 = 4 (x + 3)2 + (y − 2)2 = 4 (x − 3)2 + (y + 2)2 = 2

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Need help! Will fan and medal!! A circle is centered at (−3, 2) and has a radius of 2. Which of the following is the equation for this circle? (x + 3)2 + (y − 2)2 = 2 (x − 3)2 + (y + 2)2 = 4 (x + 3)2 + (y − 2)2 = 4 (x − 3)2 + (y + 2)2 = 2

Mathematics
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well the general form of a circle is \[(x - h)^2 + (y - k)^2 = r^2\] the centre is (h, k) and r is the radius so substitute your information and get a solution.
What numbers exactly would i be substituting @campbell_st

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well you are told the centre is (-3, 2) and radius is 2 so h = -3 k = 2 and r = 2
soo (x-3)2+ (y-2)2=4? @campbell_st
no (x - (-3))^2 + (y -2)^2 = 2^2 simplify the 1st term
What 1st term?? I'm so confused @campbell_st
Would the answer be B then?
the answer isn't B.. just substitute correctly h = - 3 so (x - h) = ( x -(-3) which becomes (x + 3)

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