A proportional relationship between the number of pounds of potatoes (x) and the price in dollars (y) is graphed, and the ordered pair (4, 3) is on the graphed line.
Part A: What is the price of 1 pound of potatoes? Show your work, including the proportion you used to determine the price. (8 points)
Part B: What does the ordered pair (8, 6) on the graph represent? Explain in words.

- anonymous

- katieb

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- anonymous

okay, so we know the equation y=mx+b

- anonymous

yea

- anonymous

but first

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- anonymous

we have to plug in (4,3) into that equation

- anonymous

ok

- anonymous

so that you can find b, right?

- anonymous

and then, from there you can draw a line and find out how much it would cost for 1

- anonymous

Ok can u stay to check my work?

- anonymous

totally

- anonymous

ill have some work too and ill snap a pic

- anonymous

wait can you help me draw the graph?

- anonymous

what do you mean? like the line?

- anonymous

Yea like how would it be presented?

- anonymous

okay so since we dont have a slope

- anonymous

we know that slope is the change in y over the change in x

- anonymous

Yea

- anonymous

so we have 3=4m+b

- anonymous

but we cant solve yet since we have two variables

- anonymous

ok ok

- anonymous

so we can do 3/4 as the slope using the given point right?

- anonymous

so now we have

- anonymous

\[3=\frac{ 3 }{ 4 }\times 4+b\]

- anonymous

ok ok

- anonymous

so what do we get when we solve that equation?

- anonymous

3?

- anonymous

or 0..

- anonymous

well, 3/4 times 4 equals three

- anonymous

correct

- anonymous

its zero

- anonymous

so the y intercept is zero

- anonymous

yay

- anonymous

so now

- anonymous

we have the equation y=3/4x+0

- anonymous

so we just plug in one for x

- anonymous

and we get y is equal to 3/4

- anonymous

ok

- anonymous

|dw:1439846550731:dw|

- anonymous

so now all i need to do is plug it i right?

- anonymous

just graph for you to visualize

- anonymous

yup

- anonymous

and then part b, means 8 pounds for 6 dollars

- anonymous

ok thank you :) :) :)

- anonymous

ok

- anonymous

your welcome! just tag if you need help again :)

- anonymous

ok :)

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