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anonymous
 one year ago
The diagram shows a rectangle ABCD. The point A is (2,14). B is (2,8) and C lies on the xaxis (?,0)
Find the equation of BC.
the coordinates of C and D.
anonymous
 one year ago
The diagram shows a rectangle ABCD. The point A is (2,14). B is (2,8) and C lies on the xaxis (?,0) Find the equation of BC. the coordinates of C and D.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One second, I have done some work, just trying to find the coordinates for C and D. Missing X values.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y8= 2/3 (x+2) for BC equation. C (?,0) D (?,6) Not sure what to do. I did slope equation. 148/2+2 = 6/4 3/2 then opp slope recip. 2/3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay @.@ may i ask what are the question that you want to ask @.@

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How to find the x values for those coordinates. :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay can you show me how you got those answers up there? cuz i confuse by your own answers and question @.@

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Apologies, I have a packet with an image. My answers are accurate, which I am completely confident of.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1The equation of line BC, in point slope form, is \(\Large y  8 = \frac{2}{3}(x+2)\). In slopeintercept form, the equation is \(\Large y= \frac{2}{3}x+\frac{20}{3}\) It doesn't matter which equation you use. Plug in y = 0 and solve for x to get the x coordinate of point C.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you explain to me how you got 20/3? @jim_thompson5910

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I see, for some reason I attempted to use outside numbers to distribute, I completely understand what I did wrong, thank you so much!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Sure. Here are the steps I did to convert from point slope form to slope intercept form. \[\Large y  8 = \frac{2}{3}(x+2)\] \[\Large y  8 = \frac{2}{3}(x)\frac{2}{3}(2)\] \[\Large y  8 = \frac{2}{3}x\frac{4}{3}\] \[\Large y  8+8 = \frac{2}{3}x\frac{4}{3}+8\] \[\Large y = \frac{2}{3}x\frac{4}{3}+8\] \[\Large y = \frac{2}{3}x\frac{4}{3}+8*\frac{3}{3}\] \[\Large y = \frac{2}{3}x\frac{4}{3}+\frac{24}{3}\] \[\Large y = \frac{2}{3}x+\frac{4+24}{3}\] \[\Large y = \frac{2}{3}x+\frac{20}{3}\]
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