For f(x) = x2 and g(x) = (x − 5)2, in which direction and by how many units should f(x) be shifted to obtain g(x)?
Up 5 units
Down 5 units
Left 5 units
Right 5 units
SOMEONE HELP FAN AND MEDAL

- brodybarnes35

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- anonymous

okay so is that x squared

- anonymous

or just 2x

- brodybarnes35

yeah squared

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## More answers

- anonymous

okay

- brodybarnes35

@abb0t @BAdhi @Cookie_2046 @dan815 @e.mccormick @Frostbite @ganeshie8 @Hero @inkyvoyd @jim_thompson5910 @keshaun455 @LunyMoony @mathway @Nnesha @oldrin.bataku @pooja195 @QueenofTamaran @Robert136 @sammixboo @tHe_FiZiCx99 @uybuyvf @Vocaloid @welshfella @xapproachesinfinity

- anonymous

okay, so we have \[x ^{2}\] and \[x ^{2}-10x+25\]

- brodybarnes35

ok so what does that mean?

- anonymous

from your answer choices, how are you going to get the first part to the second

- brodybarnes35

idk, idk how to do this lol

- anonymous

wait, you what would be easier? lol scratch everything i said

- anonymous

so

- brodybarnes35

ok :)

- anonymous

since both expressions are squared, we can square root both of them

- xapproachesinfinity

you better live it g(x)=(x-5)^2 to see what shift needed

- anonymous

meaning we just have x and x-5

- xapproachesinfinity

leave*

- anonymous

so, since you are subtracting, you are either going down or to the left

- brodybarnes35

ok

- anonymous

i wouldnt leave it if i were you actually

- brodybarnes35

ok go on please :)

- xapproachesinfinity

ok let's how you gonna do it

- xapproachesinfinity

see*

- brodybarnes35

ok

- anonymous

well we already have x and x-5, because we square rooted, and you want him to leave it as squared, thats totally fine and you can help him

- xapproachesinfinity

that's not a square root? where did you see any square root?

- xapproachesinfinity

Okay lets consider a function f(x)=x^2 we call it parent function

- brodybarnes35

ok

- xapproachesinfinity

if we want to move the graph of that function f(x) to right some units away i will use b units here
we just do the following \(f(x-b)=(x-b)^2\) that is b units to the right away ffrom f(x)
let's give this new function a name h(x) so that \(h(x)=f(x-b)=(x-b)^2\)

- xapproachesinfinity

following ?

- xapproachesinfinity

now we want to move f(x) to obtain g(x)
look at the g(x) and tell me what do you need to do to move f such that it becomes g

- xapproachesinfinity

earth to you, hello, are you there?

- brodybarnes35

yes im following

- xapproachesinfinity

so according to what i just said what can we do to shift f to get g?

- xapproachesinfinity

just compare what i did with what we have?

- brodybarnes35

i honestly dont know im guessing 5 down or to the left

- xapproachesinfinity

why down and left in my explanation i have not spelled at all any thing about down or left shifting

- xapproachesinfinity

i only i explained one thing; that is shift a curve x^2 to right by a b units to get (x-b)^2

- xapproachesinfinity

so basically to get from f(x)=x^2 to g(x)=(x-5)^2
we need to shift f(x) 5 units to the right

- brodybarnes35

can you just tell me the answer and explain cause you're not helping that well :)

- brodybarnes35

oh thanks

- brodybarnes35

so d?

- xapproachesinfinity

it is not me who is not helping it is you who don't want to be helped haha

- xapproachesinfinity

i was deriving you to the answer but you seem not to pay attention

- xapproachesinfinity

yes it is D

- brodybarnes35

ok thanks can you help on like 4 more???

- brodybarnes35

are u sure?

- brodybarnes35

@xapproachesinfinity

- xapproachesinfinity

trillion times sure! and no i can't if you don't have much interest to work the problem

- brodybarnes35

no i will i promise @xapproachesinfinity

- brodybarnes35

What is the domain of the following parabola?
u-shaped graph that opens up with a vertex of 2, negative 3
All real numbers
x ≥ 1
x ≤ 2
y ≥ −3

- brodybarnes35

@xapproachesinfinity

- brodybarnes35

help me @xapproachesinfinity

- xapproachesinfinity

all sort of parabolas have the domain all real number no matter what it is

- xapproachesinfinity

if we speak about co-domain (range) then the story is different

- brodybarnes35

so its all real numbers im assuming?wait no

- xapproachesinfinity

if you want the reason
just think is there any number that cause a function of the sort f(x)=ax^2+bx+c does not exist
i mean is there a point where that graph has discontinuity

- xapproachesinfinity

the answer is no, all real numbers are acceptable in the machine of parabolas

- brodybarnes35

so no all real numbers

- xapproachesinfinity

im saying all real numbers and you are saying no all real numbers

- xapproachesinfinity

pay a bit of attention dear :)

- brodybarnes35

ohhh ok it is all real numbers i apologize

- xapproachesinfinity

no problem

- brodybarnes35

The quadratic functions f(x) and g(x) are described as follows:
f(x) = −8x2 + 7
x g(x)
0 0
1 2
2 6
3 2
4 0
Which of the following statements best compares the maximum value of the 2 functions?
It is the same for both functions.
f(x) has a greater maximum value than g(x).
g(x) has a greater maximum value than f(x).
The maximum values cannot be determined
can u help on like 3 more? plz @xapproachesinfinity

- brodybarnes35

@xapproachesinfinity

- brodybarnes35

- brodybarnes35

@Sammylemon

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