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anonymous

  • one year ago

Coordinates for D. (?,6) C is (10,0) Rectangle ABCD. A(2,14) B(-2,8) C(10,0) D(?,6)

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. jim_thompson5910
    • one year ago
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    earlier we found line BC to be \[\Large y = -\frac{2}{3}x+\frac{20}{3}\]

  3. anonymous
    • one year ago
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    Yes, would it be the same for AD?

  4. jim_thompson5910
    • one year ago
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    no

  5. jim_thompson5910
    • one year ago
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    but the same steps will be used find the slope of AD (since it's parallel to BC, the two slopes are equal). Then use it to find the equation of line AD

  6. jim_thompson5910
    • one year ago
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    you also need the equation for line CD

  7. anonymous
    • one year ago
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    For AD equation, would it start like: y-14=m(x-2)? m = slope

  8. jim_thompson5910
    • one year ago
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    yes and m = -2/3 because AD and BC have the same slope (they are parallel lines)

  9. anonymous
    • one year ago
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    So, then I can plug in 6 to get the x value for D?

  10. jim_thompson5910
    • one year ago
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    not quite

  11. jim_thompson5910
    • one year ago
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    you'll need equation CD

  12. jim_thompson5910
    • one year ago
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    oh wait, nvm

  13. jim_thompson5910
    • one year ago
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    yes you can plug in y = 6. I didn't see D(?,6)

  14. anonymous
    • one year ago
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    Yeah, sorry, with my packet, I have image of it showing the C point being on 0. So, helped me determine the distance for the AD y and what to subtract.

  15. anonymous
    • one year ago
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    -2/3 * -2 would be 12/3?

  16. jim_thompson5910
    • one year ago
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    -2/3 * -2 = 4/3

  17. anonymous
    • one year ago
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    6-14=-2/3(x-2) -8=-2/3x + 4/3 It ends up being: 6 = -2/3x + 28/3 right?

  18. jim_thompson5910
    • one year ago
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    good

  19. jim_thompson5910
    • one year ago
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    now solve for x

  20. anonymous
    • one year ago
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    x=5?

  21. jim_thompson5910
    • one year ago
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    no

  22. jim_thompson5910
    • one year ago
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    oh I see what went wrong

  23. jim_thompson5910
    • one year ago
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    When you went from -8=-2/3x + 4/3 to 6 = -2/3x + 28/3 you made an error the 6 in ` 6 = -2/3x + 28/3` should be 0 so you should have 0 = -2/3x + 28/3

  24. jim_thompson5910
    • one year ago
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    it's 0 because you added 8 to both sides the -8 and +8 combine to 0 on the left side

  25. anonymous
    • one year ago
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    OH. x=14

  26. jim_thompson5910
    • one year ago
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    yep D is (14,6)

  27. anonymous
    • one year ago
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    To be honest, I read my graph wrong aswell, so I was confused. I lack in graphing, but all is well. You really helped and taught me a few things, I hope to remember. (:

  28. jim_thompson5910
    • one year ago
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    I'm glad I was of help

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