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anonymous
 one year ago
please help!!!! for medal!!
The function f(x) = 16(2)x represents the growth of a bee population every year in a remote swamp. Jennifer wants to manipulate the formula to an equivalent form that calculates two times a year, not just once a year. Which function is correct for Jennifer's purpose, and what is the new growth rate?
anonymous
 one year ago
please help!!!! for medal!! The function f(x) = 16(2)x represents the growth of a bee population every year in a remote swamp. Jennifer wants to manipulate the formula to an equivalent form that calculates two times a year, not just once a year. Which function is correct for Jennifer's purpose, and what is the new growth rate?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@phi i have no idea what to do

phi
 one year ago
Best ResponseYou've already chosen the best response.0maybe we write it as \[ f(x)= 16\cdot 2^x = 16 \cdot (1+1)^x \] and to change to every 6 months \[ f(x)= 16\cdot (1+1/2)^{2x}= 16 \cdot 1.5^{2x} \] but I am guessing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(x) = 16(2)x; growth rate 200% f(x) = 16(2)2x; growth rate 8% f(x) = 16(1.41)x; growth rate 8% f(x) = 16(1.41)2x; growth rate 41% these are the choices

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if this helps you @phi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okayy agian thank you so much !

phi
 one year ago
Best ResponseYou've already chosen the best response.0I guess the idea is to write the exponent as 2x (twice as many as before) but to not change things we do this \[ \left(2\right)^{\frac{1}{2} \cdot 2x } \] and then interpret that as \[ \left(2^{\frac{1}{2} }\right)^{2x} \] and 2^(1/2) is sqr(2) = 1.41, so \[ (1.41)^{2x} \] and we put the 16 in there for the final answer \[ 16(1.41)^{2x} \]
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