anonymous
  • anonymous
Find the limit of the function algebraically. limit as x approaches negative five of quantity x squared minus twenty five divided by quantity x plus five. Would the limit = -5?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
can you draw/type out the limit?
anonymous
  • anonymous
Yes @peachpi
anonymous
  • anonymous
\[\lim_{x \rightarrow -5}\frac{ x^2-25 }{ x+5}\]

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anonymous
  • anonymous
ok. can you factor the numerator?
anonymous
  • anonymous
(x+5)(x-5)
anonymous
  • anonymous
So the (x + 5) cancel and you have \[\lim_{x \rightarrow -5}x-5\] Now plug in -5 for x to get the limit
anonymous
  • anonymous
Oh so -10?
anonymous
  • anonymous
yep
anonymous
  • anonymous
Could you help me with one more?
anonymous
  • anonymous
ok
anonymous
  • anonymous
Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 16, b = 17 @peachpi
anonymous
  • anonymous
\[\frac{ \sin A }{ a }=\frac{ \sin B }{ b }\] Solve for B to get the 2nd angle of the first triangle
anonymous
  • anonymous
I did that and got b = .88 which isn't an answer choice.
anonymous
  • anonymous
anonymous
  • anonymous
That's the answer choices I'm given.
anonymous
  • anonymous
(sin 56°)/16 = (sin B)/17 sin B = (17 sin 56°)/16 sin B = 0.88 Oh, I see you. You need to take the inverse sine to find the angle. Use the sin^-1 button on your calculator \[B = \sin^{-1} 0.88 \] B = 61.74°
anonymous
  • anonymous
Oh ok, so would the answer be B then?
anonymous
  • anonymous
either B or D
anonymous
  • anonymous
Oh...so how can I decide which?
anonymous
  • anonymous
use law of sines again to test C. We know C = 62.3° in this triangle, so solve for c (sin 56°)/16 = (sin 62.3°)/c
anonymous
  • anonymous
c = 17.1, so yeah B
anonymous
  • anonymous
Ok thanks! Just did it on my calculator lol.
anonymous
  • anonymous
you're welcome

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