## anonymous one year ago Find the limit of the function algebraically. limit as x approaches negative five of quantity x squared minus twenty five divided by quantity x plus five. Would the limit = -5?

1. anonymous

can you draw/type out the limit?

2. anonymous

Yes @peachpi

3. anonymous

$\lim_{x \rightarrow -5}\frac{ x^2-25 }{ x+5}$

4. anonymous

ok. can you factor the numerator?

5. anonymous

(x+5)(x-5)

6. anonymous

So the (x + 5) cancel and you have $\lim_{x \rightarrow -5}x-5$ Now plug in -5 for x to get the limit

7. anonymous

Oh so -10?

8. anonymous

yep

9. anonymous

Could you help me with one more?

10. anonymous

ok

11. anonymous

Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. A = 56°, a = 16, b = 17 @peachpi

12. anonymous

$\frac{ \sin A }{ a }=\frac{ \sin B }{ b }$ Solve for B to get the 2nd angle of the first triangle

13. anonymous

I did that and got b = .88 which isn't an answer choice.

14. anonymous

15. anonymous

That's the answer choices I'm given.

16. anonymous

(sin 56°)/16 = (sin B)/17 sin B = (17 sin 56°)/16 sin B = 0.88 Oh, I see you. You need to take the inverse sine to find the angle. Use the sin^-1 button on your calculator $B = \sin^{-1} 0.88$ B = 61.74°

17. anonymous

Oh ok, so would the answer be B then?

18. anonymous

either B or D

19. anonymous

Oh...so how can I decide which?

20. anonymous

use law of sines again to test C. We know C = 62.3° in this triangle, so solve for c (sin 56°)/16 = (sin 62.3°)/c

21. anonymous

c = 17.1, so yeah B

22. anonymous

Ok thanks! Just did it on my calculator lol.

23. anonymous

you're welcome