anonymous
  • anonymous
The point (-3, 1) is on the terminal side of angle ?, in standard position. What are the values of sine, cosine, and tangent of ?? Make sure to show all work.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
who ever answers this will get a medl fan and some owl buck !!!!!!!!!!!!!
anonymous
  • anonymous
Let me see if i can do this...
anonymous
  • anonymous
okay ! ;)

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More answers

anonymous
  • anonymous
You can make a right triangle using that point (and the line that leads to it, which is the terminal side) by going down to the x-axis and then over to the origin.
anonymous
  • anonymous
continue
anonymous
  • anonymous
You should now have a triangle with a base that is 3 units long and a height of 1 unit. If you use the Pythagorean Theorem, you can find the hypotenuse (usually this is just left as a radical if it doesn't come out to be a nice number).
anonymous
  • anonymous
Do u understand so far?
anonymous
  • anonymous
yes
anonymous
  • anonymous
So can u find those sides?
anonymous
  • anonymous
You should have a coordinate graph for this problem, or some graph paper...
anonymous
  • anonymous
not really but iwas asking can you give me the answer for this and iwill medal fan and give you owlbuck = money ! but please this the last question then im done with alegebra 2
anonymous
  • anonymous
Lol u want the answer. Ok, but give me a minute. It's a lot better if u understand it though
anonymous
  • anonymous
It's 162!
anonymous
  • anonymous
yea its but ineed to get this over with its been stressfullol
anonymous
  • anonymous
I know how u feel btw...
anonymous
  • anonymous
and dont we all butcan show like how you got 162 cause she needs work
anonymous
  • anonymous
Work shown?
anonymous
  • anonymous
yea
anonymous
  • anonymous
The length of the y component is √(1-0)^2 +(-3-(-3))^2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) opposite The length of the x-component is √[(-3-0)^2 +(0-0)^2] = √(9+0)= 3 B(-3,0) to O(0,0) adjacent The length of vector OA is √[(-3-0)^2 + (1-0)^2] = √(9+1) = √(10) A(-3,1) to O(0,0) hypotenuse θ = 180 - α sinθ = sin(180-α) = opposite/hypotenuse = 1/√10 cosθ = adjacent/hypotenuse = -3/√10 tanθ = opposite/adjacent = 1/-3 = -1/3 α= arcsin(1/√10) ≈ 18 θ =180 -18 ≈162 WOW A LOT OF LETTERS!
anonymous
  • anonymous
And numbers...
anonymous
  • anonymous
@jammy987 u there?
anonymous
  • anonymous
yess may god bless you bro !!!!!!!!!!!!
anonymous
  • anonymous
The sin, cos, and tan values r right there... those r ur answers and ur welcome!
anonymous
  • anonymous
okay ;)
anonymous
  • anonymous
Np. :)

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