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anonymous

  • one year ago

The point (-3, 1) is on the terminal side of angle ?, in standard position. What are the values of sine, cosine, and tangent of ?? Make sure to show all work.

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  1. anonymous
    • one year ago
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    who ever answers this will get a medl fan and some owl buck !!!!!!!!!!!!!

  2. anonymous
    • one year ago
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    Let me see if i can do this...

  3. anonymous
    • one year ago
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    okay ! ;)

  4. anonymous
    • one year ago
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    You can make a right triangle using that point (and the line that leads to it, which is the terminal side) by going down to the x-axis and then over to the origin.

  5. anonymous
    • one year ago
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    continue

  6. anonymous
    • one year ago
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    You should now have a triangle with a base that is 3 units long and a height of 1 unit. If you use the Pythagorean Theorem, you can find the hypotenuse (usually this is just left as a radical if it doesn't come out to be a nice number).

  7. anonymous
    • one year ago
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    Do u understand so far?

  8. anonymous
    • one year ago
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    yes

  9. anonymous
    • one year ago
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    So can u find those sides?

  10. anonymous
    • one year ago
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    You should have a coordinate graph for this problem, or some graph paper...

  11. anonymous
    • one year ago
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    not really but iwas asking can you give me the answer for this and iwill medal fan and give you owlbuck = money ! but please this the last question then im done with alegebra 2

  12. anonymous
    • one year ago
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    Lol u want the answer. Ok, but give me a minute. It's a lot better if u understand it though

  13. anonymous
    • one year ago
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    It's 162!

  14. anonymous
    • one year ago
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    yea its but ineed to get this over with its been stressfullol

  15. anonymous
    • one year ago
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    I know how u feel btw...

  16. anonymous
    • one year ago
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    and dont we all butcan show like how you got 162 cause she needs work

  17. anonymous
    • one year ago
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    Work shown?

  18. anonymous
    • one year ago
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    yea

  19. anonymous
    • one year ago
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    The length of the y component is √(1-0)^2 +(-3-(-3))^2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) opposite The length of the x-component is √[(-3-0)^2 +(0-0)^2] = √(9+0)= 3 B(-3,0) to O(0,0) adjacent The length of vector OA is √[(-3-0)^2 + (1-0)^2] = √(9+1) = √(10) A(-3,1) to O(0,0) hypotenuse θ = 180 - α sinθ = sin(180-α) = opposite/hypotenuse = 1/√10 cosθ = adjacent/hypotenuse = -3/√10 tanθ = opposite/adjacent = 1/-3 = -1/3 α= arcsin(1/√10) ≈ 18 θ =180 -18 ≈162 WOW A LOT OF LETTERS!

  20. anonymous
    • one year ago
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    And numbers...

  21. anonymous
    • one year ago
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    @jammy987 u there?

  22. anonymous
    • one year ago
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    yess may god bless you bro !!!!!!!!!!!!

  23. anonymous
    • one year ago
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    The sin, cos, and tan values r right there... those r ur answers and ur welcome!

  24. anonymous
    • one year ago
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    okay ;)

  25. anonymous
    • one year ago
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    Np. :)

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