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anonymous
 one year ago
The point (3, 1) is on the terminal side of angle ?, in standard position. What are the values of sine, cosine, and tangent of ?? Make sure to show all work.
anonymous
 one year ago
The point (3, 1) is on the terminal side of angle ?, in standard position. What are the values of sine, cosine, and tangent of ?? Make sure to show all work.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0who ever answers this will get a medl fan and some owl buck !!!!!!!!!!!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let me see if i can do this...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can make a right triangle using that point (and the line that leads to it, which is the terminal side) by going down to the xaxis and then over to the origin.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You should now have a triangle with a base that is 3 units long and a height of 1 unit. If you use the Pythagorean Theorem, you can find the hypotenuse (usually this is just left as a radical if it doesn't come out to be a nice number).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do u understand so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So can u find those sides?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You should have a coordinate graph for this problem, or some graph paper...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not really but iwas asking can you give me the answer for this and iwill medal fan and give you owlbuck = money ! but please this the last question then im done with alegebra 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lol u want the answer. Ok, but give me a minute. It's a lot better if u understand it though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea its but ineed to get this over with its been stressfullol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know how u feel btw...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and dont we all butcan show like how you got 162 cause she needs work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The length of the y component is √(10)^2 +(3(3))^2] =√(12+ 02) = 1 A(3,1) to B(3,0) opposite The length of the xcomponent is √[(30)^2 +(00)^2] = √(9+0)= 3 B(3,0) to O(0,0) adjacent The length of vector OA is √[(30)^2 + (10)^2] = √(9+1) = √(10) A(3,1) to O(0,0) hypotenuse θ = 180  α sinθ = sin(180α) = opposite/hypotenuse = 1/√10 cosθ = adjacent/hypotenuse = 3/√10 tanθ = opposite/adjacent = 1/3 = 1/3 α= arcsin(1/√10) ≈ 18 θ =180 18 ≈162 WOW A LOT OF LETTERS!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yess may god bless you bro !!!!!!!!!!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The sin, cos, and tan values r right there... those r ur answers and ur welcome!
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