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anonymous

  • one year ago

the width of a rectangle 8in. greater than the length. the perimeter is 102in. find the dimensions of the rectangle. linear equations

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  1. anonymous
    • one year ago
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    @mathstudent55 @misty1212

  2. misty1212
    • one year ago
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    HI!! |dw:1439865489742:dw|

  3. anonymous
    • one year ago
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    HI. :)

  4. misty1212
    • one year ago
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    lets add up to find the perimeter

  5. misty1212
    • one year ago
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    \[x+x+8+x+x+8=4x+16\] right?

  6. anonymous
    • one year ago
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    right

  7. misty1212
    • one year ago
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    and you know that is (102\) so your job is to solve \[4x+16=102\] for \(x\)

  8. misty1212
    • one year ago
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    can you do that?

  9. anonymous
    • one year ago
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    yes

  10. misty1212
    • one year ago
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    ok let me know what you get

  11. anonymous
    • one year ago
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    kk one sec

  12. anonymous
    • one year ago
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    -26

  13. anonymous
    • one year ago
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    @misty1212

  14. misty1212
    • one year ago
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    oh no

  15. misty1212
    • one year ago
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    \[4x+16=102\] first subtract \(16\) from both sides

  16. anonymous
    • one year ago
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    -86

  17. anonymous
    • one year ago
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    @misty1212

  18. mathstudent55
    • one year ago
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    You did 16 - 102. You need to do 102 - 16

  19. anonymous
    • one year ago
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    ohhhhh

  20. anonymous
    • one year ago
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    86-

  21. anonymous
    • one year ago
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    @misty1212 @mathstudent55

  22. mathstudent55
    • one year ago
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    Good, Now you have 4x = 86

  23. anonymous
    • one year ago
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    21.5

  24. misty1212
    • one year ago
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    lol what does \(86-\) mean ??

  25. mathstudent55
    • one year ago
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    Correct.

  26. anonymous
    • one year ago
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    thanks. :)

  27. mathstudent55
    • one year ago
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    That is x. Now you need x + 8 = 21.5 + 8 What is 21.5 + 8 ?

  28. anonymous
    • one year ago
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    one sec

  29. anonymous
    • one year ago
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    29.5

  30. mathstudent55
    • one year ago
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    Correct.

  31. anonymous
    • one year ago
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    thanks.

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