the width of a rectangle 8in. greater than the length. the perimeter is 102in. find the dimensions of the rectangle. linear equations

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the width of a rectangle 8in. greater than the length. the perimeter is 102in. find the dimensions of the rectangle. linear equations

Mathematics
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HI!! |dw:1439865489742:dw|
HI. :)

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Other answers:

lets add up to find the perimeter
\[x+x+8+x+x+8=4x+16\] right?
right
and you know that is (102\) so your job is to solve \[4x+16=102\] for \(x\)
can you do that?
yes
ok let me know what you get
kk one sec
-26
oh no
\[4x+16=102\] first subtract \(16\) from both sides
-86
You did 16 - 102. You need to do 102 - 16
ohhhhh
86-
Good, Now you have 4x = 86
21.5
lol what does \(86-\) mean ??
Correct.
thanks. :)
That is x. Now you need x + 8 = 21.5 + 8 What is 21.5 + 8 ?
one sec
29.5
Correct.
thanks.

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