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anonymous
 one year ago
the width of a rectangle 8in. greater than the length. the perimeter is 102in. find the dimensions of the rectangle.
linear equations
anonymous
 one year ago
the width of a rectangle 8in. greater than the length. the perimeter is 102in. find the dimensions of the rectangle. linear equations

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathstudent55 @misty1212

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1HI!! dw:1439865489742:dw

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1lets add up to find the perimeter

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[x+x+8+x+x+8=4x+16\] right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1and you know that is (102\) so your job is to solve \[4x+16=102\] for \(x\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok let me know what you get

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[4x+16=102\] first subtract \(16\) from both sides

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You did 16  102. You need to do 102  16

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@misty1212 @mathstudent55

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Good, Now you have 4x = 86

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1lol what does \(86\) mean ??

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1That is x. Now you need x + 8 = 21.5 + 8 What is 21.5 + 8 ?
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