anonymous
  • anonymous
the width of a rectangle 8in. greater than the length. the perimeter is 102in. find the dimensions of the rectangle. linear equations
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@mathstudent55 @misty1212
misty1212
  • misty1212
HI!! |dw:1439865489742:dw|
anonymous
  • anonymous
HI. :)

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More answers

misty1212
  • misty1212
lets add up to find the perimeter
misty1212
  • misty1212
\[x+x+8+x+x+8=4x+16\] right?
anonymous
  • anonymous
right
misty1212
  • misty1212
and you know that is (102\) so your job is to solve \[4x+16=102\] for \(x\)
misty1212
  • misty1212
can you do that?
anonymous
  • anonymous
yes
misty1212
  • misty1212
ok let me know what you get
anonymous
  • anonymous
kk one sec
anonymous
  • anonymous
-26
anonymous
  • anonymous
@misty1212
misty1212
  • misty1212
oh no
misty1212
  • misty1212
\[4x+16=102\] first subtract \(16\) from both sides
anonymous
  • anonymous
-86
anonymous
  • anonymous
@misty1212
mathstudent55
  • mathstudent55
You did 16 - 102. You need to do 102 - 16
anonymous
  • anonymous
ohhhhh
anonymous
  • anonymous
86-
anonymous
  • anonymous
@misty1212 @mathstudent55
mathstudent55
  • mathstudent55
Good, Now you have 4x = 86
anonymous
  • anonymous
21.5
misty1212
  • misty1212
lol what does \(86-\) mean ??
mathstudent55
  • mathstudent55
Correct.
anonymous
  • anonymous
thanks. :)
mathstudent55
  • mathstudent55
That is x. Now you need x + 8 = 21.5 + 8 What is 21.5 + 8 ?
anonymous
  • anonymous
one sec
anonymous
  • anonymous
29.5
mathstudent55
  • mathstudent55
Correct.
anonymous
  • anonymous
thanks.

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