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anonymous
 one year ago
i need help What is the simplified form of the fifth root of x to the fourth power times the fifth root of x to the fourth power?
anonymous
 one year ago
i need help What is the simplified form of the fifth root of x to the fourth power times the fifth root of x to the fourth power?

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.2\[\sqrt[5]{x^4}\times \sqrt[5]{x^4}\]??

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2first add up the exponents inside the radical (i.e. multiply) and get \[\sqrt[5]{x^8}\] but that is not the final answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.010 /8 i add all the exponents

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2since 5 goes in to 8 one time, with a remainder of 3, the final answer is \[x^1\sqrt[5]{x^3}\] or just \[x\sqrt[5]{x^3}\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2you have it upside down dear, and the addition is not quite right \[\huge x^{\frac{4}{5}}\times x^{\frac{4}{5}}=x^{\frac{8}{5}}\] since \[\huge \frac{4}{5}+\frac{4}{5}=\frac{8}{5}=1\tfrac{3}{5}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh i seee noww......

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the solution of 5 times the square root of the quantity of x plus 7 equals negative 10, and determine if it is an extraneous solution. x = −3; extraneous x = −3; not extraneous x = 11; extraneous x = 11; not extraneous

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2that may be a good explanation of why the answer is \[x\sqrt[5]{x^3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my friend got A and i think is C who's right ?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2it is certainly extraneous, i.e. there is no solution so why should you have to try and find it i have no idea

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2i guess they want you to square both sides \[25(x+7)=100\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2divide by 25 get \[x+7=4\] so \[x=3\] really it is a bad question though

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2oh sorry, your friend is right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh i used the wrong operation :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Given the functions f(x) = −2x − 1 and g(x) = −3x + 4, which operation results in the smallest coefficient on the x term? Addition Subtraction Multiplication Two operations result in the same coefficient

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is another one we are arguing about. she thinks its B i go with D

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2add and get \(5x+3\) subtract and get who knows because we don't know which one gets subtracted from which, but either way you will not get \(5x\) you will get either \(x\) or \(x\)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2oh wait, i didn't multiply yet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i read to her what you wrote she thinks its A

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2if you multiply you get \[6 x^25 x4\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2so the answer is actually D, two operations result in the same coefficient, addition and multiplication

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol yeah im helping her. shes been struggling

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2i can always tell flvs questions by how bad they are

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol finally someone agrees... lol but thanks again for helping me i'll fan you okok
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