anonymous
  • anonymous
i need help What is the simplified form of the fifth root of x to the fourth power times the fifth root of x to the fourth power?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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misty1212
  • misty1212
HI!!
anonymous
  • anonymous
hi i need help
misty1212
  • misty1212
\[\sqrt[5]{x^4}\times \sqrt[5]{x^4}\]??

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More answers

anonymous
  • anonymous
yess
misty1212
  • misty1212
first add up the exponents inside the radical (i.e. multiply) and get \[\sqrt[5]{x^8}\] but that is not the final answer
anonymous
  • anonymous
10 /8 i add all the exponents
misty1212
  • misty1212
since 5 goes in to 8 one time, with a remainder of 3, the final answer is \[x^1\sqrt[5]{x^3}\] or just \[x\sqrt[5]{x^3}\]
misty1212
  • misty1212
you have it upside down dear, and the addition is not quite right \[\huge x^{\frac{4}{5}}\times x^{\frac{4}{5}}=x^{\frac{8}{5}}\] since \[\huge \frac{4}{5}+\frac{4}{5}=\frac{8}{5}=1\tfrac{3}{5}\]
anonymous
  • anonymous
ohh i seee noww......
anonymous
  • anonymous
Find the solution of 5 times the square root of the quantity of x plus 7 equals negative 10, and determine if it is an extraneous solution. x = −3; extraneous x = −3; not extraneous x = 11; extraneous x = 11; not extraneous
misty1212
  • misty1212
that may be a good explanation of why the answer is \[x\sqrt[5]{x^3}\]
anonymous
  • anonymous
my friend got A and i think is C who's right ?
misty1212
  • misty1212
it is certainly extraneous, i.e. there is no solution so why should you have to try and find it i have no idea
misty1212
  • misty1212
i guess they want you to square both sides \[25(x+7)=100\]
misty1212
  • misty1212
divide by 25 get \[x+7=4\] so \[x=-3\] really it is a bad question though
misty1212
  • misty1212
oh sorry, your friend is right
anonymous
  • anonymous
oh i used the wrong operation :(
anonymous
  • anonymous
Given the functions f(x) = −2x − 1 and g(x) = −3x + 4, which operation results in the smallest coefficient on the x term? Addition Subtraction Multiplication Two operations result in the same coefficient
anonymous
  • anonymous
this is another one we are arguing about. she thinks its B i go with D
misty1212
  • misty1212
ya'll both wrong
anonymous
  • anonymous
ohhhhh why?
misty1212
  • misty1212
add and get \(-5x+3\) subtract and get who knows because we don't know which one gets subtracted from which, but either way you will not get \(-5x\) you will get either \(-x\) or \(x\)
misty1212
  • misty1212
oh wait, i didn't multiply yet
anonymous
  • anonymous
i read to her what you wrote she thinks its A
misty1212
  • misty1212
if you multiply you get \[6 x^2-5 x-4\]
misty1212
  • misty1212
so the answer is actually D, two operations result in the same coefficient, addition and multiplication
anonymous
  • anonymous
lol soo i was right
misty1212
  • misty1212
let me guess FLVS?
anonymous
  • anonymous
lol yeah im helping her. shes been struggling
misty1212
  • misty1212
i can always tell flvs questions by how bad they are
anonymous
  • anonymous
lol finally someone agrees... lol but thanks again for helping me i'll fan you okok

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